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MrMuchimi
3 years ago
7

Last semester, 2/3 more students were taking soccer than were taking tennis class. The tennis claw had 129 students in it. How m

any students were in the soccer class?
Mathematics
1 answer:
Semenov [28]3 years ago
8 0

There were 215 students in soccer class.

Step-by-step explanation:

Given,

Number of students in tennis class = 129

2/3 of tennis class students = \frac{2}{3}*129= 2*43

2/3 of tennis class students = 86

Number of soccer students = Number of tennis students + 2/3 of tennis students

Number of soccer students = 129+86

Number of soccer students = 215

There were 215 students in soccer class.

Keywords: fraction, addition

Learn more about fractions at:

  • brainly.com/question/11175936
  • brainly.com/question/11203617

#LearnwithBrainly

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Approximate the change in the volume of a sphere when its radius changes from r= 5ft to r= 5.1ft (v(r)= 3/4 pi r^3)?
leva [86]

Answer:

18.03 cubic feet

Step-by-step explanation:

Hello,

Step 1

find the volume of the sphere when radius= 5 ft

v(r)= \frac{3}{4} \pi r^3\\v(5)= \frac{3}{4}\pi (5\ ft)^3\\v(5)= \frac{3}{4}\pi *125\ ft^{3} \\v(5)=294.52\ cubic\ feet\\

Step 2

find the volume of the sphere when radius= 5.1 ft

v(r)= \frac{3}{4}\pi r^3\\v(5.1)= \frac{3}{4} \pi (5.1\ ft)^3\\v(5.1)= \frac{3}{4}\pi *132.651\ ft^{3} \\v(5.1)=312.551\ cubic\ feet\\\\

Step 3

Compare the Volumes to find the change

\frac{v(r_{2})}{v(r_{1})} =\frac{312.551}{294.52} =1.06

the volumen of the sphere with radius = 5.1 is 1.06 times bigger than the first one(r=5)

Now, find the change

change= {v(r_{2})-{v(r_{1})}} \\change=312.551\ cubic\ feet\ -294.52 cubic feet \\ change=18.031\ cubic\ feet

change=18.03 cubic feet

Have a great day.

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