Question

उक्त समयमा बसले कति दुरी पार गर्दछ ? Abusstarts from

Answer 1

Answer:

The magnitude of the velocity will be 60 m/s.

The distance covered is 3,600 m

Step-by-step explanation:

Constant Acceleration Motion

It's known as a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

If a is the constant acceleration, vo is the initial speed, vf the final speed, and t the time, the following relation applies:

$v_f=v_o+at$

The distance traveled by the object is calculated as:

$\displaystyle x=v_o.t+\frac{a.t^2}{2}$

The bus starts from rest, i.e. vo=0, the acceleration is a=0.5 m/s^2. The magnitude of the velocity at t=2 minutes = 120 seconds is:

$v_f=0+0.5\cdot 120=60 \ m/s$

The magnitude of the velocity will be 60 m/s.

The distance covered during that time is:

$\displaystyle x=0+\frac{0.5\cdot 120^2}{2}$

$\displaystyle x=\frac{7,200}{2}$

x = 3,600 m

The distance covered is 3,600 m