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Roman55 [17]
3 years ago
9

Standard form of a point that goes through-2,4 and the slope is -1/7

Mathematics
1 answer:
lesantik [10]3 years ago
8 0

<u>Answer:</u>

Standard form of a line passing through (-2, 4) and having slope of  -1/7 is x + 7y = 26

<u>Solution:</u>

Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7

Standard form of line passing through point ( a , b ) and having slope m is given by

(y – b) = m ( x – a)   --------(1)

In our case given point is ( -2 , 4 ) and slope is -1/7 that means

a = -2 , b = 4 , m = -(1/7)

On substituting given value of a , b and m is equation (1) we get

(y-4)=\left(-\frac{1}{7}\right)(x-(-2))

=>(y-4)=\left(-\frac{1}{7}\right)(x+2)

=> 7( y - 4 ) = -x – 2

=> 7y + x = -2 + 28

=> x + 7y = 26  

Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26

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What 6 ways can you write 835,000
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3 years ago
4x + 16/12 What is the value of x in the equation= x - 4?
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I hope this helps, if any doubt leave a comment

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2 years ago
Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i
Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let <em>X</em> = <em>r</em><em> </em>= a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = <em>p</em> = 0.35.

The sample selected is of size <em>n</em> = 12.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 12 and <em>p</em> = 0.35.

The probability function of a binomial random variable is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x}

(a)

For <em>X</em> = 0 the probability is:

P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006

For <em>X</em> = 1 the probability is:

P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037

For <em>X</em> = 2 the probability is:

P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

E(X)=np

The expected number of vehicles out of 12 that will tailgate is:

E(X)=np=12\times0.35=4.2

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

SD(X)=np(1-p)

The standard deviation of vehicles out of 12 that will tailgate is:

SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

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3 years ago
Which best describes a system of equations that has no solution?
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Answer: inconsistent

Step-by-step explanation:

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