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3 years ago

Standard form of a point that goes through-2,4 and the slope is -1/7

Mathematics

1 answer:

lesantik [10]3 years ago

8 0

Answer:

Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26

Solution:

Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7

Standard form of line passing through point ( a , b ) and having slope m is given by

(y – b) = m ( x – a) --------(1)

In our case given point is ( -2 , 4 ) and slope is -1/7 that means

a = -2 , b = 4 , m = -(1/7)

On substituting given value of a , b and m is equation (1) we get

$(y-4)=\left(-\frac{1}{7}\right)(x-(-2))$

$=>(y-4)=\left(-\frac{1}{7}\right)(x+2)$

=> 7( y - 4 ) = -x – 2

=> 7y + x = -2 + 28

=> x + 7y = 26

Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26

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a ) See step by step explanation

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Step-by-step explanation:

The definition of type of user x is:

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if x > 400 minutes per month high user

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Then:

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(xt) xt xt+1

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High(1) or H 0,3 0,7

The resulting equation system is:

xt = 0,8* xt + 0,2* xt+1

xt+1 = 0,3*xt + 0,7* xt+1

1 = xt + xt+1

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xt - 0,6*xt = 0,2

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In february teh % of low user customer wll be

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0,5 = 0,8*0,5 + 0,2*xt+1

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