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Roman55 [17]
3 years ago
9

Standard form of a point that goes through-2,4 and the slope is -1/7

Mathematics
1 answer:
lesantik [10]3 years ago
8 0

<u>Answer:</u>

Standard form of a line passing through (-2, 4) and having slope of  -1/7 is x + 7y = 26

<u>Solution:</u>

Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7

Standard form of line passing through point ( a , b ) and having slope m is given by

(y – b) = m ( x – a)   --------(1)

In our case given point is ( -2 , 4 ) and slope is -1/7 that means

a = -2 , b = 4 , m = -(1/7)

On substituting given value of a , b and m is equation (1) we get

(y-4)=\left(-\frac{1}{7}\right)(x-(-2))

=>(y-4)=\left(-\frac{1}{7}\right)(x+2)

=> 7( y - 4 ) = -x – 2

=> 7y + x = -2 + 28

=> x + 7y = 26  

Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26

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