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4 years ago

50 points ! marking brainly to whoever gets all 5 correct !

Mathematics

1 answer:

Svetradugi [14.3K]4 years ago

3 0

1. 5

2. 7-3 root 3

3. 6

4. 4.24

5. 5.76

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Pls dont guess on it

yuradex [85]

Answer:

2(8a + 8)

Step-by-step explanation:

The easiest way to do this is to substitute a for a number. For example, let's just make things easy and make a = 1.

So, if a = 1, the expression 16a + 8 would be 16(1) + 8 = 24.

Let's find all the expressions that would also equal 24 if a = 24.

Plug in 1 for a in each of the equations. You will find that 2(8a + 8) will not equal 24 if a equals 1.

2(8a + 8)

2(8(1) + 8

2(8 + 8)

2(16)

4 0

2 years ago

¿Por qué un conjunto numerable es una función biyectiva?????

WITCHER [35]

En matemáticas, un conjunto contable es un conjunto con la misma cardinalidad (número de elementos) que un subconjunto del conjunto de números naturales. Un conjunto contable es un conjunto finito o un conjunto contable infinito.

8 0

4 years ago

I need to know the answer to the question with the circle

KATRIN_1 [288]

___________________________

◆ AREA RELATED TO CIRCLES ◆ ___________________________

As shown in the figure ,

Radius of circle = 5 cm

Side of square = 2 × (Radius of inscribed circle)

Side of square = 2 × 5 cm

Side of square = 10 cm = a

___________________________

Now ,
Area of shaded region = (Area of square) - ( Area of inscribed circle )

Area of shaded region =
${a}^{2} - \pi {r}^{2}$

Area of shaded region =
${10}^{2} - \frac{22}{7} \times {5}^{2}$

Area of shaded region = 100 - 78.571

$= 21.428 \: ans.$

7 0

4 years ago

10h + 3y + 6 -4h -y -2 simplified

Svetach [21]

Answer:

6 h + 2 y + 4 is your answer

Step-by-step explanation:

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box

pantera1 [17]

To find the z-score for a weight of 196 oz., use

$z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2$

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.

7 0

4 years ago