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Lana71 [14]
3 years ago
13

How do you so this?​

Mathematics
1 answer:
marissa [1.9K]3 years ago
6 0

(1÷2)×(1÷2)×(1÷2)×(1÷2)×(1÷2)

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How do I do this? Find the distance between the points given. Simplify all irrational answers.
belka [17]
The formula for finding the distance between points is √(x-x₁)²+(y-y₁)²
x=0, y=6, x₁=5, y₁=12
√(0-5)²+(6-12)²
√(-5)²+(-6)²
√25+36
√61 is irrational
7.81 points(rounded to nearest hundredth) is the distance between those two points.
8 0
4 years ago
Please help me with this problem​
Nookie1986 [14]
In order for two lines to be perpendicular, their slopes must multiply together to equal to negative one
So we do negative one divided by 2/5 to get the slope of the red line
Which is -5/2
To check, we do 2/5 multiplied by -5/2 which equals to -1 so our answer is correct
8 0
4 years ago
Read 2 more answers
Solve for the variable x.
inna [77]

Answer:

<u>x = 5</u>

Step-by-step explanation:

Equating the terms :

  • x + 3 = 2x - 2

Add 2 on both sides :

  • x + 3 + 2 = 2x - 2 + 2
  • x + 5 = 2x

Subtract x from both sides :

  • x + 5 - x = 2x - x
  • <u>x = 5</u>
3 0
2 years ago
Helppppppppppppp pleaseeeeeeeeeeeeeeee
strojnjashka [21]

Answer:

The answer would be b, 8:13

4 0
3 years ago
GIVING BRAINLIESTTTTT
andreev551 [17]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3. Place the compass pin on point C and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

* Lets find the same steps in the constructions

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  "Place the compass on a point on the original line"

6 0
3 years ago
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