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2 years ago

What is 12 divided 155 WITHOUT DECIMALS BTW the problem involves long division

Mathematics

2 answers:

s344n2d4d5 [400]2 years ago

6 0

I can give you a fraction instead:

12/155= a fraction, when you input it in a calculator.

so, you would do 12/1 times 1/155. When you want to divide fractions, you use a reciprocal. This is when you kind of flip the numerator and denominator. Also, when you want to turn whole numbers into fractions, you just make a dividing bar (fraction) and use 1 as the denominator.
Ok, so next, you do 12 times one. That's 12. Then, you do 1 times 155. That's 155. Your final answer should be 12/155. Sorry if it's wrong, but this is the only way I could think of w/o decimals

Crazy boy [7]2 years ago

5 0

Answer:

12 R11 or 12 11/12

Step-by-step explanation:

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densk [106]

Use PEMDAS, the answer that I got is 19.

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2 years ago

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Billy puts $4900 in a bank that pays 6% annually.

Maru [420]

If it's adding to the 4,900 in the bank just add the numbers to 4,900.

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3 years ago

How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%

blondinia [14]

The trick is to exploit the difference of squares formula,

$a^2-b^2=(a-b)(a+b)$

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

$(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2$

Whatever you do to the denominator, you have to do to the numerator too. So

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2$

Expand the numerator:

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)$

$(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}$

So we have

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2$

But √12 = √(3•4) = 2√3, so

$\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}$

7 0

2 years ago

A student receives test scores of 62, 83, and 91. This student's term project score is 88. Each test is worth 20% of the final g

miskamm [114]

Answer:

The student's current average score will be 69.2

Step-by-step explanation:

Let first test be TEST A: which is 20 of total and secures 62

Let second test be TEST B: which is 20 of the total marks and has secured 83.

Let third test be TEST C: which is 20 of total and has secured 91.

And now the TEST D which is 25 of total and has secured 88.

Therefore, by multipying across

${0.2}\times{62}$ = 12.4

${0.2}\times{83}$ = 16.6

${0.2}\times{91}$ = 18.2

${0.25}\times{88}$ =22

Now, by adding the scores to get the average score

We get, 69.2.

6 0

2 years ago

Find the distance between (2,7) and (-6,-2)

stepladder [879]

Answer: $\sqrt{145}$

Step-by-step explanation:

1. use the distance formula!

$distance = \sqrt{(x_{2} - x_{1})^{2} +{(y_{2} - y_{1})}^2$

2. then using the distance formula with (2, 7) and (-6, -2) you get...

$distance= \sqrt{2 -(-6)^2 +(7 - (-2)^2}$

$distance= \sqrt{8^2 +9^2}$

$distance= \sqrt{64 +81}$

$distance= \sqrt{145}$

$\sqrt{145}$ is the simplest radical form

6 0

3 years ago