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3 years ago

Write a numerical expression that represents a number that is 5 greater than 3

1 answer:

8 0

Numerical expression that will represents this:
5 is greater than 3
=> greater than symbol in mathematical is >
Thus the numerical expression of the said equation is:
=> 5 > 3
Which is really true because number 5 is greater than 3.
If we do it in reverse way, this will be like this.
3 is lesser than 5, which is equals to:
=> 3 < 5
We, also have = sign
For example:
3 = 3 or 5 = 5

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Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

8 0

3 years ago

20.8 divided by 100 how is the decimal point moved

alukav5142 [94]

Answer:

Two points to the left

Step-by-step explanation:

20.8/100 = 0.208

The number was 20.8, but now the new number moved

1. 2.08

2. 0.208

So my answer is two decimal points to the left.

I hope this helped!

6 0

2 years ago

Called ultimate addition, u(x) is defined to be the sum of all digit of an integer until the result is single digit integer. If

slamgirl [31]

<h3>Answer: A) 2</h3>

=====================================================

Work Shown:

u(50654) = 5+0+6+5+4 = 20

u(20) = 2+0 = 2

u(50654) = 2

We want to find all possible values of m such that u(m) = 2 and also m is some two-digit integer.

-----

Possible values of m are: m = 11, m = 20

u(m) = u(11) = 1+1 = 2

u(m) = u(20) = 2+0 = 2

and that's it. There are no other ways to have two positive integers add up to 2.

5 0

3 years ago

a man and a daughter stand on a scale they weigh 90kg. The man gets back on with his cat together they weigh 70kg. The daughter

Marta_Voda [28]

The man weighs 60kg. The daughter weighs 30kg. The cat weighs 10kg.

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