Ask question

Ask question

All categories

2 years ago

11

How many outcomes are possible when choosing a vowel and choosing a card suit (spades, clubs, hearts or diamonds)?

1 answer:

Vilka [71]2 years ago

7 0

There are six vowels and 4 card suits
Each vowel can pick from 4 suits so 4*6=24
24 outcomes

You might be interested in

I need answers to these MCAS practice questions ASAP!

Semmy [17]

I’ve attached a photo with my work ....
Hope it helps!!

8 0

2 years ago

Carl opened a bank account that does not earn interest with $900. He deposits $30 per week. After how many weeks will Carl have

Inessa [10]

Answer:

B i worked it out in my head, sorry if i dont get it right

3 0

2 years ago

Read 2 more answers

A recipe for 8 people includes 4 pounds of sugar. How many pounds of sugar would be necessary for 6 people?

sammy [17]

Answer:

3pound sugar .,......................

3 0

2 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

2 years ago

Simplify the expression: 42 + 8 ÷ 2.

igor_vitrenko [27]

Your final answer is 25

4 0

2 years ago