<span>
y = 7 + 3/5
y = 35/5 + 3/5
y = 38/5
y = 2*(38/5)
y = 76/10
---
lunch time:
z = 1/2
z = 5*(1/2)
z = 5/10
---
time switching classes:
w = 7/10
---
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (76/10 - 5/10 - 7/10)/6
x = (76 - 5 - 7)/(10*6)
x = (64)/(10*6)
x = (2*2*2*2*2*2)/(2*5*2*3)
x = (2*2*2*2)/(5*3)
x = 16/15
x = 1.0666666666
---
check:
y = 7 + 3/5
y = 7.6
z = 1/2
z = 0.5
w = 7/10
w = 0.7
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (7.6 - 0.5 - 0.7)/6
x = 1.0666666666
answer:
1.07 hours</span>
Answer:
6cm
Step-by-step explanation:
Answer:
b = 4
Step-by-step explanation:
5-1=5b-4b
4=b
Answer:
252.3110
Step-by-step explanation:
Answer:
it will take 1.4 hours for the two trains to be 294 miles apart
Step-by-step explanation:
Let t be the time taken for each train
The westbound train travels at 95 miles per hour.
Speed of westbound train = 95
time = t
Distance = speed * time = 95 t
The eastbound train travels at 115 miles per hour
Speed of eastbound train = 115
time = t
Distance = speed * time = 115 t
both trains are 294 miles apart means the distance between both trains are 294 miles
So we add the distance of both trains and set it equal to 294
95t + 115t = 294
210 t =294
t = 1.4
So, it will take 1.4 hours for the two trains to be 294 miles apart
