Answer:
The standard form is 8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11
The degree of given polynomial is '5'
the co-efficient of y⁴ is '-17'
Step-by-step explanation:
Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵
<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>
<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>
now Given polynomial is 2 y²+ 6 y³-11-17 y⁴+8 y⁵
The standard form is
8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11
<u><em>Conclusion</em></u>:-
<em>The degree of given polynomial is '5'</em>
<em>The co-efficient of y⁴ is '-17'</em>
<em> </em>
Answer: 6x^7+ 12x^6+ 3x^5
Hope that helped
Answer:
f
(
x
)
=
−
1
2
x
2
+
3
x
−
1
2
Explanation:
A quadratic function can be written in vertex form as:
f
(
x
)
=
a
(
x
−
h
)
2
+
k
where
(
h
,
k
)
is the vertex and
a
is a constant multiplier.
In our example the vertex
(
h
,
k
)
is
(
3
,
4
)
, so we can write:
f
(
x
)
=
a
(
x
−
3
)
2
+
4
Given that this passes through the point
(
1
,
2
)
, we must have:
2
=
a
(
1
−
3
)
2
+
4
=
4
a
+
4
Subtract
4
from both ends to get:
−
2
=
4
a
Divide both sides by
4
and transpose to find:
a
=
−
1
2
So our quadratic function can be written in vertex form as:
f
(
x
)
=
−
1
2
(
x
−
3
)
2
+
4
We can multiply this out and simplify as follows:
f
(
x
)
=
−
1
2
(
x
−
3
)
2
+
4
f
(
x
)
=
−
1
2
(
x
2
−
6
x
+
9
)
+
4
f
(
x
)
=
−
1
2
x
2
+
3
x
−
9
2
+
4
f
(
x
)
=
−
1
2
x
2
+
3
x
−
1
2
Step-by-step explanation:
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Answer
I think the answer is C if its not then say the answer in the comments.
Step-by-step explanation:
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Answered by : ❝ AǫᴜᴀWɪᴢ ❞
