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3 years ago

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What's the word name for 20,004? A. Two thousand four B. Two hundred thousand four C. Twenty thousand four D. Twenty thousand fo

rty

1 answer:

Vika [28.1K]3 years ago

8 0

Answer:

C

Step-by-step explanation:

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Can you please help me with this

Brrunno [24]

Just do 2000-586.40 and that will get you the remaining money they need to raise!:)

6 0

3 years ago

Read 2 more answers

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0). Which type of triangle is ∆ABC? Select All that apply.

stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(5-(-3))^2+(8-2)^2}$

$AB=\sqrt{(8)^2+(6)^2}$

$AB=\sqrt{64+36}$

$AB=\sqrt{100}$

$AB=10$

Similarly,

$BC=\sqrt{(11-5)^2+(0-8)^2}$

$BC=\sqrt{(6)^2+(8)^2}$

$BC=\sqrt{36+64}$

$BC=\sqrt{100}$

$BC=10$

And,

$AC=\sqrt{(11-(-3))^2+(0-2)^2}$

$AC=\sqrt{(14)^2+(-2)^2}$

$AC=\sqrt{196+4}$

$AC=\sqrt{200}$

$AC=10\sqrt{2}$

Two sides of the triangle are equal, i.e., $AB=BC$ . So, the triangle is an isosceles triangle.

Sum of square of two smaller side is

$AB^2+BC^2=10^2+10^2$

$AB^2+BC^2=100+100$

$AB^2+BC^2=200$

$AB^2+BC^2=AC^2$

Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

7 0

3 years ago

Multiplying intergers practice look at pic

ale4655 [162]

1)-3,551
2)-6,014
3)-70
4)6,474
5)2,703
6)-5,795
7)1,679
8)1,488
9)6,510
10)513
11)-1,071
12)-660

4 0

3 years ago

Read 2 more answers

I have to get this so I pass help plz

pshichka [43]

Answer:

$\boxed{\sf x=-2}$

$\boxed{\sf y=-4}$

Step-by-step explanation:

<u>First, Let's solve for x in -2x+2y=-4:</u>

$\sf -2x+2y=-4$

<u>Subtract 2y from both sides:</u>

$\sf -2x+2y-2y=-4-2y$

$\sf -2x=-4-2y$

<u>Divide both sides by -2:</u>

$\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}$

$\bold{ x=y+2}$

<u>Now, we'll substitute x=y+2 to 3x+3y=-18:</u>

$\sf 3x+3y=-18$

→ let x=2+y

$\sf 3\bold{(2+y)}+3y=-18$

<u>Simplify:</u>

$\sf 6+6y=-18$

<u>Now, let's solve for y in 6+6y=-18</u>

$\sf 6+6y=-18$

<u>Subtract 6 from both sides:</u>

$\sf 6+6y-6=-18-6$

$\sf 6y=-24$

<u>Divide both sides by 6:</u>

$\sf \cfrac{6y}{6}=\cfrac{-24}{6}$

$\bold{ y=-4}$

<u>Now, substitute y=-4 into x=2+y:</u>

$\sf x=2+y$

→ let y = -4

$\sf x=2+\bold{-4}$

$\bold{x=-2}$

Therefore, x=-2 and y=-4.

<u>_____________________________________</u>

5 0

2 years ago

How do you solve a proportion? (Like not how To but What do i do Because the question Is how do you solve a proportion.)

maksim [4K]

Answer:

By cross-multiplying?

3 0

3 years ago