Ask question

Ask question

All categories

4 years ago

15

Fffsdfwfsdcwcv≥≥≥≥≥≥≥≥≥≥≥≥≥≥≥≥≥f

1 answer:

irakobra [83]4 years ago

6 0

Answer:

...

Step-by-step explanation:

You might be interested in

Select the correct answer.

Solnce55 [7]

Answer: the answer would be 1/8

Step-by-step explanation:

in decimal form it would be 0.125 so the answer is 1/8

hope this helps.

4 0

3 years ago

Read 2 more answers

A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4

vlabodo [156]

Answer:

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

Step-by-step explanation:

Bernoulli's equation,

$P_1+\frac12 \rho v^2_1+\rho g h_1= P_2+\frac12 \rho v^2_2+\rho g h_2$

P₁ = P₂= atmospheric presser

$\rho$ = density

$\frac12 \rho v^2_1+\rho g h_1= \frac12 \rho v^2_2+\rho g h_2$ [since P₁ = P₂]

$\Rightarrow\rho (\frac12 v^2_1+ g h_1)= \rho(\frac12 v^2_2+ g h_2)$

$\Rightarrow\frac12 v^2_1+ g h_1= \frac12 v^2_2+ g h_2$

$\Rightarrow\frac12 v^2_2-\frac12 v^2_1=g h_1- g h_2$

$\Rightarrow v^2_2- v^2_1=2g h$ [ $h_1-h_2=h$ ]

Here $v_1\approx 0$

$\Rightarrow v^2_2=2g h$

$\therefore v_2=\sqrt {2gh$

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole $v_2$ = $\sqrt {2\times 9.8\times 10.4}$ m/s

=14.28 m/s.

Given, the rate of flow from the leak is $2.53\times 10^{-3}$ $m^3/min$

$=\frac{2.53\times 10^{-3}}{60}$ $m^3/s$

Let the diameter of the hole be d.

Then the cross section area of the hole is $=\pi (\frac d2)^2$

We know that,

The rate of flow = Cross section area × speed

$\Rightarrow \frac{2.53\times 10^{-3}}{60} =\pi (\frac d2)^2\times 14.28$

$\Rightarrow (\frac d2)^2=\frac{2.53\times 10^{-3}}{60\times 14.28\times \pi}$

$\Rightarrow d= 1.94 \times 10^{-3}$

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

4 0

4 years ago

Open Response Factor 12m + 5n. Explain<br> how you found your answer. (Lesson 4)

Brilliant_brown [7]

Answer:

how are u hottie here's my pfp

Step-by-step explanation:

4 0

2 years ago

Match the equation below with the following graph.

frutty [35]

It’s the last one: 2x+1=-x+7

7 0

3 years ago

The mass of a pencil is 5.44 g. The mass of a crayon is 2.13 g.

amm1812

It's asking what the size of the pencil is in terms of the crayon...

5.44/2.13=2.55388061

The pencil is 2.6 times larger

7 0

3 years ago