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Volgvan
2 years ago
7

Nth term of 4,10,16,12

Mathematics
1 answer:
enyata [817]2 years ago
4 0

the 9th term for 4,10,16,12 is add 6

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A home is to be built on a 56 foot 9 inch wide lot. The house is 5 feet 5 inches from the side of the lot and is 34 feet 10 inch
ch4aika [34]

Answer:

=16 ft 6 in

Step-by-step explanation:

Remainder side = Total lot - house -other side

=(56 ft 9 in) - (34 ft 10 in) - (5 ft 5 in)

=(55 ft 21 in) - (34 ft 10 in) - (5 ft 5 in)

=16 ft 6 in

8 0
2 years ago
A family built a house and wanted to put down in their rectangular yard. The sod costs $0.32 per square foot plus 10 per square
sammy [17]

Answer:

The total cost of purchasing and laying sods in the rectangular yard is $2,146.67  

Step-by-step explanation:

We are given the following in the question:

Dimensions of rectangular yard:

Length = 50 feet

Width = 30 feet

Area of rectangular yard =

A = \text{Length}\times \text{Width}\\A = 50\times 30\\A  = 1500\text{ square feet}

Cost of sod = $0.32 per square foot

Total cost of sod =

C_1 = \text{Unit cost of sod}\times \text{Area of yard}\\C_1 = 0.32\times 1500\\C_1 = 480\$

Cost of laying sods = $10 per square yard

Total cost of laying sod =

C_2 = \text{Unit cost of laying sod}\times \text{Area of yard}\\\\\text{1 square yard}=\dfrac{1}{9}\text{Square foot}\\\\C_2 = 10\times \dfrac{1500}{9}\\\\C_2 = 1666.67\$

Total cost of purchasing and laying the sod =

C = C_1 + C_2\\C = 480 +1666.67\\C = \$2,146.67

Thus, the total cost of purchasing and laying sods in the rectangular yard is $2,146.67

3 0
3 years ago
Find the sum of the first 9 terms of the following sequence. Round to the nearest
aivan3 [116]

Answer:

Your missing a number and your answer is 12

Step-by-step explanation:

4 0
3 years ago
Please help!! ALgebra 2 <br> I will be h=giving out extra points the the brainiest answers
Arte-miy333 [17]

Answer:

B

Step by Step Explanation

4 0
2 years ago
A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult
klio [65]

Answer:

<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>

Step-by-step explanation:

Probability = \frac{Required outcomes}{Total possible outcomes}

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

<em>Total possible outcomes: 20</em>


<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = \frac{n(Odd)}{Total} = \frac{10}{20} = \frac{1}{2} = 0.5


Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = \frac{n(5)}{Total} = \frac{4}{20} = \frac{1}{5} = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = \frac{2}{20}=\frac{1}{10}=0.1

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6

7 0
3 years ago
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