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3 years ago

What is the solution to the following system? X+2y+z=9 X-y+3z=13 2z=10

Mathematics

1 answer:

Vinvika [58]3 years ago

5 0

Answer: x = 0; y = 2; z = 5

Step-by-step explanation:

x+2y+z=9

x-y+3z=13

2z=10

Start with the last equation: 2z = 10, therefore z = 5 [easy]

Let's rewrite the second equation with 1) z=5, and 2) rearrange to find x:

x-y+3z = 13

x - y +3*5 = 13

x = y-2

Now use the values for x [(y-2)] and y [5] in the first equation:

X+2y+z=9

(y-2) +2y + 5 = 9

3y +3 = 9

3y = 6

y = 2

Now that we have y [2] and z [5], let's use the first equation to solve for x:

x+2y+z=9

x + 4 + 5 = 9

x + 9 = 9

x = 0

====

Try the three values (x=0, y=2, and z=5) in any of the formulas. The result should/will equal the number shown.

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10 months ago

1. A heterozygous white-fruited squash plant is crossed with a yellow-fruited plant, yielding 200 seeds. of these seeds, 110 pro

garri49 [273]

Answer:

Part 1 , not significant

Part II, significant

Step-by-step explanation:

Given that a heterozygous white-fruited squash plant is crossed with a yellow-fruited plant, yielding 200 seeds. of these seeds, 110 produce white-fruited plants while only 90 produce yellow-fruited plants

$H_0: Both colours are equally likely\\H_a: Both colours are not equally likely$

(Two tailed chi square test)

We assume H0 to be true and find out expected

If H0 is true expected would be 100 white and 100 yellow

Chi square = $\Sigma \frac{(O-E)^2}{E} \\=\frac{(110-100)^2}{100} +frac{(90-100)^2}{100} \\=2$

df = 1

p value = 0.152799

Since p value > 0.05 at 5% level we accept that the colours are equally likely

Here observed are 1100 and 900

Expected 1000 & 1000

df = 1

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p value <0.0001

These results are here statistically significant.

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Step-by-step explanation:

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