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Ghella [55]
2 years ago
8

7 friends share 840g of chocolate equally between them.

Mathematics
2 answers:
Lilit [14]2 years ago
8 0

Answer:

he is definitely correct bcz u have to change the g into kg first then solve

nataly862011 [7]2 years ago
3 0

Answer:

he is wrong

Step-by-step explanation:

.12g/840g= 7000

this means that he is wrong because 7000 is larger than 7

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The author of Passage 1 mentions the "sermon"
Tanzania [10]

The author of Passage 1 mentions the "sermon" (line 35) primarily in order to: remind the readers of a significant obligation to King (Option E).

<h3>What is a comprehension passage?</h3>

In a comprehension passage, some questions are given that follow the passage. The questions are to be answered by using the data given in the passage, even if it differs from real-life facts.

Now,

  • In line 35, the mention of the word "sermon" shows that everyone owes him for the type of person he was, for all that he did for everyone and especially the Black Americans, with the reference to the sermon he preached "Ingratitude".

Hence, Option E is the most suitable option, i.e., The author of Passage 1 mentions the "sermon" (line 35) primarily in order to: remind the readers of a significant obligation to King (Option E).

To learn more about comprehension passages, refer to the link:

brainly.com/question/24716030

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1 year ago
How many groups of 1/4 are in 3. Draw a tape diagram
BaLLatris [955]

Answer:

12 groups of 1/4

Step-by-step explanation:

Look up the tape diagram part

8 0
3 years ago
A class has 11 students who are to be assigned seating by lot.
Rainbow [258]

Answer:

it would be c

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Answers should be exact decimals (please do not leave as fractions or unfinished calculations). A six-sided die (cube) with face
Ghella [55]

Answer:

(a) P = 0.0001

(b) P = 0.6561

(c) P = 0.2916

(d) P = 0.3439

(e) P = 0.2

Step-by-step explanation:

This is a probability problem.

The dice is rolled 4 times (n=4) and we calculate the probability of different outcomes.

The probability of a 6 in a roll is 0.5.

The probability of a 1, 2, 3, 4 or 5 in a roll is 0.5/5=0.1.

<u />

<u>a) Outcome: all the rolls are 2.</u>

The probability of having a 2 in a roll is 0.1, so we can calculate the probability of having a 2 in four consecutive rolls as

P(x1=2;x2=2;x3=2;x4=2)=P(x=2)^4=0.1^4=0.0001

<u>b) Outcome: none of the rolls is a 2.</u>

The probability of having any other number but 2 in 4 rolls is:

P(x1\neq2;x2\neq2;x3\neq2;x4\neq2)=P(x\neq2)^4=(1-0.1)^4=0.6561

<u>c) Outcome: exactly one roll is a 2</u>

This is the sum of the probability of having a 2 in the first, second, third or fouth roll, and others numbers in the rest of the rolls. These 4 combinations have the same probability, so we will multiply it by 4.

P(exactly \,one\,2)=4*P(x1=2;x2\neq2;x3\neq2;x4\neq2)\\\\P(exactly \,one\,2)=4*0.1*0.9*0.9*0.9=0.2916

<u>d) Outcome: at least one of the rolls is a 2</u>

In this case, is the probability of having at least one 2, is the sum of the probability of getting a 2 in the first roll, the probability of getting a 2 in the second roll, the probability of getting a 2 in the third roll and the probability of getting a 2 in the four roll:

P(x1=2)+P(x2=2)+P(x3=2)+P(x4=2)=0.1+0.9*0.1+0.9*0.9*0.1+0.9*0.9*0.9*0.1\\\\P(x1=2)+P(x2=2)+P(x3=2)+P(x4=2)=0.1+0.09+0.081+0.0729\\\\P(x1=2)+P(x2=2)+P(x3=2)+P(x4=2)=0.3439

<u>e) Outcome: either the first roll or the last roll is a 2</u>

The probability of getting a 2 in the first roll is equal to having it in a fourth roll, and its the probability of getting a 2 in a roll (multiplied by 2, beacuse there can be either in the first or in the last roll).

P(x1=2)+P(x4=2)=2*P(x=2)=2*0.1=0.2

6 0
3 years ago
Find the given higher-order derivative.<br><br> f''(x) = 9- 3/x<br><br> f'''(x)=
Genrish500 [490]

Answer:

f'''(x)=\frac{3}{x^{2}}

Step-by-step explanation:

We are given with Second-order derivative of function f(x).

f''(x)=9-\frac{3}{x}

We need to find Third-order derivative of the function f(x).

f''(x)=9-\frac{3}{x}=9-3x^{-1}

We know that,

f'''(x) = (f''(x))'

So,

f'''(x)=\frac{\mathrm{d}\,f''(x)}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,(9-3x^{-1})}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,9}{\mathrm{d} x}-\frac{\mathrm{d}\,3x^{-1}}{\mathrm{d} x}

f'''(x)=0-3\frac{\mathrm{d}\,x^{-1}}{\mathrm{d} x}

f'''(x)=-3(-1)x^{-1-1}

f'''(x)=3x^{-2}

f'''(x)=\frac{3}{x^{2}}

Therefore, f'''(x)=\frac{3}{x^{2}}

4 0
4 years ago
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