compared to the energy released per mole of reactant during chemical reactions the energy released per mole of reactant during n
1 answer:
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Explanation:
2, 8, 8, 2 is the electron arrangement of Calcium.
The way that the "orbitals", the shells, fill up is given as . . . etc etc.
It is more stable for the fourth shell to start filling up with an electron pair, and then subsequent electrons filling up the third shell again.
So while potassium 19, is 2,8,8,1
And calcium 20, is 2,8,8,2
Scandium 21 will fill up as, 2,8,9,2
This will continue until we reach Zinc 30, which will fill up as 2,8,18,2. The third shell is now "full", and the fourth shell will now being to fill up.
The fourth orbital starts getting filled up again, Gallium 31, is 2,8,18,3
<u>Answer:</u> The ideal yield of carbon dioxide is 7.506 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of carbon monoxide = 5.61 g
Molar mass of carbon monoxide = 28 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of carbon monoxide and water follows:
By Stoichiometry of the reaction:
1 mole of carbon monoxide produces 1 mole of carbon dioxide
So, 0.200 moles of carbon monoxide will produce = of carbon dioxide
Now, calculating the mass of carbon dioxide from equation 1, we get:
Molar mass of carbon dioxide = 44 g/mol
Moles of carbon dioxide = 0.200 moles
Putting values in equation 1, we get:
To calculate the experimental yield of carbon dioxide, we use the equation:
Percentage yield of carbon dioxide = 85.3 %
Theoretical yield of carbon dioxide = 8.8 g
Putting values in above equation, we get:
Hence, the ideal yield of carbon dioxide is 7.506 grams