The most obvious answer for this would be a product i think.
A. The patch's area in square kilometers (km²) is 1.61×10⁻⁹ km²
B. The cost of the patch to the nearest cent is 734 cents
<h3>A. How to convert 16.1 cm² to square kilometers (km²)</h3>
We can convert 16.1 cm² to km² as illustrated below:
Conversion scale
1 cm² = 1×10⁻¹⁰ km²
Therefore,
16.1 cm² = 16.1 × 1×10⁻¹⁰
16.1 cm² = 1.61×10⁻⁹ km²
Thus, 16.1 cm² is equivalent to 1.61×10⁻⁹ km²
<h3>B. How to determine the cost in cent</h3>
We'll begin by converting 16.1 cm² to in². This can be obtained as illustrated below:
1 cm² = 0.155 in²
Therefore,
16.1 cm² = 16.1 × 0.155
16.1 cm² = 2.4955 in²
Finally, we shall the determine the cost in centas fo r llow:
- Cost per in² = $2.94 = 294 cent
- Cost of 2.4955 in² =?
1 in² = 294 cent
Therefore,
2.4955 in² = 2.4955 × 294
2.4955 in² = 734 cents
Thus, the cost of the patch is 734 cents
Learn more about conversion:
brainly.com/question/2139943
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"High-intensity" storms produce larger drops that fall faster than those of "low-intensity"storms and therefore have greater ability to destroy and dislodge particles from the soil matrix.
Hope that helped :)
CCl₄ - carbon tetrachloride
This molecule has 4 polar bonds, but is non-polar in nature.
:)
Answer:
3.45 moles Li contains 2.08 × 10 (to the power of)24 atoms .
Explanation:
The relationship between atoms and moles is:
1 mole atoms =
6.022 × 10 (to the power of)23
atoms
In order to determine how many atoms occupy a given number of moles, multiply the given moles by
6.022 × 10 (to the power of)23
atoms/mole
.
In the case of 3.45 moles lithium (Li):
3.45 mol Li × 6.022 × 10 (to the power of)23 atoms Li/ 1 mol Li =
2.08 × 10 (to the power of)24
atoms Li rounded to three
