The answer is w⁻²/v⁻².

v/w raised to the second power is (v/w)²

(v/w)² = v²/w²

Since xᵃ = 1/x⁻ᵃ, then v²/w² = 1/v⁻²w²

Since 1/xᵃ = x⁻ᵃ, then 1/v⁻²w² = w⁻²/v⁻²

8 0

2 years ago

Pls help me with this:((

BlackZzzverrR [31]

Answer:

9. A. One - to - One Correspondence

10. D. None of the above

5 0

2 years ago

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What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

7 0

3 years ago

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