We have to use the functions:
h ( x ) = 2 x + 5 and t ( x ) = 7 x - 6
Part A:
( h + t ) ( x ) = ( 2 x + 5 ) + ( 7 x - 6 ) = 9 x - 1
Part B :
( h · t ) ( x ) = ( 2 x + 5 ) · ( 7 x - 6 ) = 14 x² - 12 x + 35 x - 30 =
= 14 x² + 23 x - 30
Part C :
h [ t ( x ) ] = h ( 7 x - 6 ) = 2 · ( 7 x - 6 ) + 5 = 14 x - 12 + 5 =
= 14 x - 7
The highlighted sector is exactly 3/4 of the circle area, because
is 3/4 of
which is a complete rotation.
Since you are given the radius, you can compute the area as

So, 3/4 of this area would be
squared cm.
The remaining sector, of course, is
squared cm.
Answer:
3x - y + 7 = 0
Step-by-step explanation:
The given point is , ( -4 , -5) and the slope is 3. The point slope form is ,
=> y - y₁ = m( x - x₁)
=> y - (-5) = 3 { x - (-4) }
=> y +5 = 3( x + 4 )
=> y + 5 = 3x + 12
=> 3x - y + 12 - 5 = 0
=> 3x - y +7 = 0
<h3>
<u>Hence</u><u> the</u><u> </u><u>equation</u><u> of</u><u> the</u><u> line</u><u> is</u><u> </u><u>3x</u><u> </u><u>-</u><u> </u><u>y </u><u>+</u><u> </u><u>7</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>.</u></h3>