So, you need 10 penny, 4 nickles and 7 dimes
Lets, check it.
According to the question,
total coins = 21
7 + 4 + 10 = 21
21 = 21.........................................true
Now,
their value should equal $1.00 = 100 cents
Penny = 1 cent
nickle = 5 cent
dime = 10 cent,
So,
(10 *1) + (4 * 5) + (7 * 10) = 100
10 + 20 + 70 = 100
100 = 100......................................true
So, you need 10 penny, 4 nickle, and 7 dimes
<span>The correct answer is 1 16/25.
Explanation<span>:
This is read as "one and sixty-four one-hundredths." This means the fraction would be 1 64/100.
Both numerator and denominator are even, so we will divide both by 2 and get 1 32/50.
Again, both are even, so we divide by 2 again and get 1 16/25.</span></span>
Answer:
See below ~
Step-by-step explanation:
Sides of a rhombus are equal.
⇒ QT = TS
⇒ x² - 4x - 10 = 6x + 14
⇒ x² - 10x - 24 = 0
⇒ x² + 2x - 12x - 24 = 0
⇒ x (x + 2) - 12 (x + 2) = 0
⇒ (x + 2)(x - 12) = 0
⇒ x = -2 or x = 12
Substitute both values and see which gives a positive value for QT :
<u>When x = -2</u> :
- QT = (-2)² - 4(-2) - 10
- QT = 4 + 8 - 10
- QT = 2
<u>When x = 12</u> :
- QT = (12)² - 4(12) - 10
- QT = 144 - 48 - 10
- QT = 86
The 2 possible answers are :
- x = -2, QT = 2
- x = 12, QT = 86
