For any point to be in the first quadrant, it must have a positive "x" value and "y" value.
If x = 1 then y = 2, a point with both x and y positive values which would be in the First Quadrant.
She ate 1/8 of the cornbread, and this is fully simplified as well.
L=2W+3, A=LW, using L from the first in the second gives you:
A=(2W+3)W
A=2W^2+3W, and we are told A=90 so
2W^2+3W=90
2W^2+3W-90=0
2W^2-12W+15W-90=0
2W(W-6)+15(W-6)=0
(2W+15)(W-6)=0, since W>0 for all real possibilities,
W=6ft, and since L=2W+3
L=15ft
So the pool will be 6 ft wide by 15 ft long.
Answer:
B. Multiply the divisor and dividend by 100.
Step-by-step explanation:
Multiply by 100 to get rid of the decimal
