Answer:
![\iint_D 8y^2 \ dA = \dfrac{88}{3}](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D%20%5Cdfrac%7B88%7D%7B3%7D)
Step-by-step explanation:
The equation of the line through the point
&
can be represented by:
![y-y_o = m(x - x_o)](https://tex.z-dn.net/?f=y-y_o%20%3D%20m%28x%20-%20x_o%29)
Making m the subject;
![m = \dfrac{y_1 - y_0}{x_1-x_0}](https://tex.z-dn.net/?f=m%20%3D%20%5Cdfrac%7By_1%20-%20y_0%7D%7Bx_1-x_0%7D)
∴
we need to carry out the equation of the line through (0,1) and (1,2)
i.e
y - 1 = m(x - 0)
y - 1 = mx
where;
![m= \dfrac{2-1}{1-0}](https://tex.z-dn.net/?f=m%3D%20%5Cdfrac%7B2-1%7D%7B1-0%7D)
m = 1
Thus;
y - 1 = (1)x
y - 1 = x ---- (1)
The equation of the line through (1,2) & (4,1) is:
y -2 = m (x - 1)
where;
![m = \dfrac{1-2}{4-1}](https://tex.z-dn.net/?f=m%20%3D%20%5Cdfrac%7B1-2%7D%7B4-1%7D)
![m = \dfrac{-1}{3}](https://tex.z-dn.net/?f=m%20%3D%20%5Cdfrac%7B-1%7D%7B3%7D)
∴
![y-2 = -\dfrac{1}{3}(x-1)](https://tex.z-dn.net/?f=y-2%20%3D%20-%5Cdfrac%7B1%7D%7B3%7D%28x-1%29)
-3(y-2) = x - 1
-3y + 6 = x - 1
x = -3y + 7
Thus: for equation of two lines
x = y - 1
x = -3y + 7
i.e.
y - 1 = -3y + 7
y + 3y = 1 + 7
4y = 8
y = 2
Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7
∴
![\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D%20%5Cint%5E2_1%20%5Cint%20%5E%7B-3y%2B7%7D_%7By-1%7D%20%5C%208y%5E2%20%5C%20dxdy)
![\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cint%5E2_1%20%5Cint%20%5E%7B-3y%2B7%7D_%7By-1%7D%20%5C%20y%5E2%20%5C%20dxdy)
![\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg) dy](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cint%5E2_1%20%20%5Cbigg%20%28%20%5Cint%5E%7B-3y%2B7%7D_%7By-1%7D%20%5C%20dx%20%5Cbigg%29%20%20%20dy)
![\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cint%5E2_1%20%20%5Cbigg%20%28%20%5Bxy%5E2%5D%5E%7B-3y%2B7%7D_%7By-1%7D%20%5Cbigg%20%29%20%5C%20dy)
![\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cint%5E2_1%20%20%5Cbigg%20%28%20%5By%5E2%28-3y%2B7-y%2B1%29%5D%5Cbigg%20%29%20%5C%20dy)
![\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ([y^2(-4y+8)] \bigg ) \ dy](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cint%5E2_1%20%20%5Cbigg%20%28%5By%5E2%28-4y%2B8%29%5D%20%5Cbigg%20%29%20%5C%20dy)
![\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( -4y^3+8y^2 \bigg ) \ dy](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cint%5E2_1%20%20%5Cbigg%20%28%20-4y%5E3%2B8y%5E2%20%5Cbigg%20%29%20%5C%20dy)
![\iint_D 8y^2 \ dA =8 \bigg [\dfrac{ -4y^4}{4}+\dfrac{8y^3}{3} \bigg ]^2_1](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cbigg%20%5B%5Cdfrac%7B%20-4y%5E4%7D%7B4%7D%2B%5Cdfrac%7B8y%5E3%7D%7B3%7D%20%5Cbigg%20%5D%5E2_1)
![\iint_D 8y^2 \ dA =8 \bigg [ -y^4+\dfrac{8y^3}{3} \bigg ]^2_1](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cbigg%20%5B%20-y%5E4%2B%5Cdfrac%7B8y%5E3%7D%7B3%7D%20%5Cbigg%20%5D%5E2_1)
![\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cbigg%20%5B%20-2%5E4%2B%5Cdfrac%7B8%282%29%5E3%7D%7B3%7D%20%2B%201%5E4-%20%5Cdfrac%7B8%5Ctimes%20%281%29%5E3%7D%7B3%7D%5Cbigg%5D)
![\iint_D 8y^2 \ dA =8 \bigg [ -16+\dfrac{64}{3} + 1- \dfrac{8}{3}\bigg]](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cbigg%20%5B%20-16%2B%5Cdfrac%7B64%7D%7B3%7D%20%2B%201-%20%5Cdfrac%7B8%7D%7B3%7D%5Cbigg%5D)
![\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cbigg%20%5B%20-15%2B%20%5Cdfrac%7B64-8%7D%7B3%7D%5Cbigg%5D)
![\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cbigg%20%5B%20-15%2B%20%5Cdfrac%7B56%7D%7B3%7D%5Cbigg%5D)
![\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{-45+56}{3}\bigg]](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cbigg%20%5B%20%20%5Cdfrac%7B-45%2B56%7D%7B3%7D%5Cbigg%5D)
![\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{11}{3}\bigg]](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D8%20%5Cbigg%20%5B%20%20%5Cdfrac%7B11%7D%7B3%7D%5Cbigg%5D)
![\iint_D 8y^2 \ dA = \dfrac{88}{3}](https://tex.z-dn.net/?f=%5Ciint_D%208y%5E2%20%5C%20dA%20%3D%20%5Cdfrac%7B88%7D%7B3%7D)
Answer:
A.The answer four square root of two plus ten is irrational because the sum of a rational number and irrational number is an irrational number.
Step-by-step explanation:
Given the question as 4√2 + 5√4 the sum is
4√2 + 5*√4
4√2 + 5*2
4√2 + 10
Putting an irrational number in decimal form, it goes on forever without repeating.
4*√2 +10 = 4× 1.41421356237 +10
=15.6568542495----------------which irrational
Answer:
3/ and 2/4X70$= C
Step-by-step explanation:
Answer:
Point A to point F and point I to point H would have the ratio of 2:1.
The general statement that is true about retirement is <em>B. your </em><em>income </em><em>will decrease, while your </em><em>expenses </em><em>will increase.</em>
Retirement is the leaving of one's of occupation. This means you cease to be involved in active service in a job or occupation especially when one is considered old and of retirement age.
During retirement, retirement benefits and pension are usually made available to retirees. However, one's income will come to a decline which makes most people scared of retirement. Keeping up with the standard of living they are used to becomes difficult as income to sustain such may not be available.
Therefore, the general statement that is true about retirement is <em>B. your </em><em>income </em><em>will decrease, while your </em><em>expenses </em><em>will increase.</em>
<em />
Learn more about retirement on:
brainly.com/question/3063811