Question

Graph a parabola whose vertex is at (3,5) with y-intercept at y=1

Answer 1

I wich i knew the answer to this dang it

Answer 2

Answer:

Graph

Step-by-step explanation:

Given: Vertex: (3,5) and y-intercept at y=1

Passing point: (0,1)

Vertex form of parabola:

$y=a(x-h)^2+k$

where, (h,k) is vertex.

$y=a(x-3)^2+5$

Passing point: (0,1)

$1=a(0-3)^2+5$

$a=-\dfrac{4}{9}$

Equation of parabola:

$y=-\dfrac{4}{9}(x-3)^2+5$

Plot vertex and y-intercept for graph.

Please see the attachment for graph.