1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
____ [38]
3 years ago
14

An inflatable beach ball has a circumference of 141.3 centimeters what is the volume of the beach ball when fully inflated

Mathematics
1 answer:
Naddik [55]3 years ago
4 0

The volume of fully inflated ball is 47688.75 cubic centimeter

Step-by-step explanation:

Step 1 :

The circumference of the given beach ball = 141.3 centimeters

We need to find volume of the inflated ball

Step 2 :

Circumference  = 2 \pi r = 141.3 [r is the radius]

=> r =  22.5 [ This is obtained by dividing 141.3 by 2  \pi]

The volume of the fully inflated ball is the volume of a sphere with the radius 22.5

Therefore volume = (4/3)  \pi r³ =  (4/3)  \pi (22.5)³ = 47688.75 cubic centimeter

Step 3 :

Answer :

The volume of fully inflated ball is 47688.75 cubic centimeter

You might be interested in
The angle measures of triangle QRS are given:
Trava [24]

Answer:

x = 15°

Step-by-step explanation:

(5x-15) + 75 + 3x = 180

8x + 60 = 180

8x = 120

x = 15°

7 0
3 years ago
Karen's aunt is buying peaches to make peach cobbler. She needs 6 peaches for each cobbler.
QveST [7]

Answer:

A. 72

Step-by-step explanation:

If she is making 12 cobblers and needs 6 peaches per one.

She needs 72 (6 times 12= 72) or ( 6c = 72)

8 0
2 years ago
Read 2 more answers
The answer I got is not one of the options, and I am very confused, because now I don't know what to do?
Effectus [21]
<span>A’(2, -4); B’(7, -9); C’(-2, -9)
I believe you did it correctly but over the wrong line. You were supposed to do it over line M and it looks like you did it over the X-axis.</span>
4 0
3 years ago
Jina made $154 for 11 hours of work. at the same rate, how much would she make for 17 hours of work?
Lynna [10]
14$ per hour
238$ for 17 hours
6 0
3 years ago
Are the following triangles similar? Justify your answer.
Ber [7]

Answer:

Yes they are similar.

There are three similarity criteria for triangles.

The first one (AAA) , your case, says that two triangles are similar if their corresponding angles are equal.

The second one (SAS) says that two triangles are similar if two sides have lengths in the same ratio and the angles that are included in these two sides are equal.

The third one (SSS) says that two triangles are similar of all of their sides have lengths in the same ratio.

About the first criteria, you actually need only two corresponding angles to be the same, because the third will always be the difference between 180° and the two angles.

Remember that you CANNOT exceed 180° for the sum of the three angles of a triangle.

And remember also that similarity involves correspondence in sides and angles. Two triangles, with same angles, but mirrored, are not similar!

7 0
3 years ago
Other questions:
  • 20 hundreds = how many thousands
    14·1 answer
  • In 2000, the number of students enrolled at Arlington Country Day School was 823 students. In 2010, the population was approxima
    12·2 answers
  • What is the area of this figure?
    11·1 answer
  • one winter day the temperature ranged from a high of 20 f to a low of -25 f. by how many degrees did the temperature change?
    15·1 answer
  • 1. In quantum physics what is entanglement ?
    15·1 answer
  • The donations by a restaurant to a certain charity, y, will be two-fifths of its profits, x, plus $50. How can you determine the
    11·2 answers
  • Bottom#6 <br> Round answer to the nearest hundredth.
    12·1 answer
  • Which statement is true about the extreme value of the given quadratic equation? A. The equation has a maximum value with a y-co
    14·1 answer
  • Jasmon spent half of her weekly
    10·1 answer
  • Hey guys! ima just randomly thank people and rate their answers! plus fe points!
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!