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ad-work [718]
3 years ago
6

NH4+(aq) + NO2−(aq) → N2(g) + 2H2O(l) is given by rate = k[NH4+][NO2−]. At a certain temperature, the rate constant is 4.10 × 10

−4 /M·s. Calculate the rate of the reaction at that temperature if [NH4+] = 0.301 M and [NO2−] = 0.160 M.
Chemistry
1 answer:
arlik [135]3 years ago
8 0

Answer:

rate = 1.97\times 10^{-5}\ M/s

Explanation:

Given that:-

rate = k[NH_4^+][NO_2^-]

k = 4.10\times 10^{-4}\ /Ms

[NH_4^+]=0.301\ M

[NO_2^-]=0.160\ M

So,

rate = 4.10\times 10^{-4}\times 0.301\times 0.160\ M/s=1.97\times 10^{-5}\ M/s

<u>1.97\times 10^{-5}\ M/s is the rate of the reaction at that temperature if [NH4+] = 0.301 M and [NO2−] = 0.160 M.</u>

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