Answer:
12.2329 atm
Explanation:
Applying
PV = nRT.................... Equation 1
Make P the subject of the equation
P = (n/V)RT................ Equation 2
Where P = Osmotic pressure, (n/V) = Molarity of urea, T = Temperature, R = molar gas constant.
From the question,
Given: (n/V) = 0.5 M, T = 25°C = (273+25) = 298 K, R = 0.0821 Latm/mol.K
Substitute these values into equation 2
P = (0.5)(298)(0.0821)
P = 12.2329 atm
Air pollution is the addition of impurities to the atmosphere. A physicist would be concerned because pollutants can reduce sunlight reaching the earth and this quantity, radiation, would fall under the scope of a physicist. Physicists might also be concerned with the absorption of heat by certain pollutants. They would be concerned with studying how much heat is absorbed by each molecule to ascertain the impact of the entire contamination in the atmosphere.
Answer:
Pb²⁺(aq) --> Ni²⁺(aq)
Explanation:
The equation of the reaction is given as;
Ni(s) + Pb(NO₃)₂(aq) --> Pb(s) + Ni(NO₃)₂(aq)
In writing the ionic equation, we break the aqueous compound into ions. The solid and liquid compounds are ignored.
We have;
Pb²⁺(aq) + NO₃²⁻(aq) --> Ni²⁺(aq) + NO₃²⁻(aq)
Canceling the spectator ions;
Pb²⁺(aq) --> Ni²⁺(aq)
Answer:
See picture for answer
Explanation:
First to all, an aldehyde is a carbonated chain with a Carbonile within it chain. It's call aldehyde basically because the C = O is always at the end of the chain. When the C = O is on another position of the chain, is called a ketone.
Now, in this exercise we have an aldehyde with 5 carbons, so the first carbon is the C = O. The remaining four carbon belong to the chain. however, we need to have a branched chain in this molecular formula.
If this the case, this means that the longest chain cannot have 5 carbons. It should have 4 carbons as the longest chain. The remaining carbon, would one branched.
In this case, we only have two possible ways to have an aldehyde with a branched chain, and 4 carbons at max. One methyl in position 2, and the other in position 3.
The remaining aldehyde with branched chain, cannot have 4 carbons as longest, it should have 3 carbons with longest chain and 2 carbons as radicals (In this case, methyl). In this way, we just have all the aldehyde with this formula and at least one branched chain. The other possible ways would be conformers or isomers of the first three.
See picture for the structures of these 3 aldehydes, and their names.}
1. 1 2 1 2
2. 2 1 1 1
3. 2 2 2 1
4. 1 2 1 2
5. 2 3 2 3