Vinegar contains an organic compound with the following functional group. What type of organic compound is vinegar an example of
?
The functional group contains a carbonyl group, which is a carbon atom double-bonded to an oxygen atom, bonded to a carbon chain on one side of its carbon atom and a hydroxyl group, which is an oxygen atom single-bonded to a hydrogen atom, on the other side.
Amine
Aldehyde
Carboxylic acid
Ester
The functional group contains a carbonyl group, which is a carbon atom double-bonded to an oxygen atom, bonded to a carbon chain on one side of its carbon atom and a hydroxyl group, which is an oxygen atom single-bonded to a hydrogen atom, on the other side.
Amine
Aldehyde
Carboxylic acid
Ester
1 answer:
Answer:
Option-C (Carboxylic Acid)
Explanation:
Vinegar is a solution made up of 95 % water and 5 % Acetic Acid. The structure of Acetic Acid is shown below. Acetic acid belongs to a class of organic compounds called as Caboxylic Acids. The functional group of carboxylic acid contain a carbonyl group bonded to hydroxyl group and an alkyl group (highlighted red in structure).
Due to acid nature of this class it can donate the proton bonded to oxygen atom next to carbonyl group and resulting in the formation of resonance stabilized carboxylate ion.
Other examples of Carboxylic acids are,
HCOOH Formic Acid
CH₃-COOH Acetic Acid
CH₃-CH₂-COOH Propionic Acid
CH₃-CH₂-CH₂-COOH Butanoic Acid
CH₃-CH₂-CH₂-CH₂-COOH Pentanoic Acid
Option-C (Carboxylic Acid)
Explanation:
Vinegar is a solution made up of 95 % water and 5 % Acetic Acid. The structure of Acetic Acid is shown below. Acetic acid belongs to a class of organic compounds called as Caboxylic Acids. The functional group of carboxylic acid contain a carbonyl group bonded to hydroxyl group and an alkyl group (highlighted red in structure).
Due to acid nature of this class it can donate the proton bonded to oxygen atom next to carbonyl group and resulting in the formation of resonance stabilized carboxylate ion.
Other examples of Carboxylic acids are,
HCOOH Formic Acid
CH₃-COOH Acetic Acid
CH₃-CH₂-COOH Propionic Acid
CH₃-CH₂-CH₂-COOH Butanoic Acid
CH₃-CH₂-CH₂-CH₂-COOH Pentanoic Acid
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Answer:
Explanation:
Given parameters:
pH = 3.50
Unknown:
concentration of [H₃0⁺] = ?
concentration of [OH⁻] = ?
Solution:
In order to find the unknown, we use some simple expressions which best explains the pH scale and the equilibrium systems of aqueous solutions.
pH = -log₁₀[H₃O⁺]
[H₃O⁺] = inverse log₁₀ (-pH) = =
[H₃O⁺] = 3.2 x 10⁻⁴moldm⁻³
For the [OH⁻]:
we use : pOH = -log₁₀ [OH⁻]
Recall: pOH + pH = 14
pOH = 14 - pH = 14 - 3.5 = 10.5
Now we plug the value of pOH into pOH = -log₁₀ [OH⁻]
[OH⁻] =
[OH⁻] = = 3.2 x 10⁻¹¹moldm⁻³
The solution is acidic as the concentration of H₃0⁺ is more than that of the OH⁻ ions.