Vinegar contains an organic compound with the following functional group. What type of organic compound is vinegar an example of
?
The functional group contains a carbonyl group, which is a carbon atom double-bonded to an oxygen atom, bonded to a carbon chain on one side of its carbon atom and a hydroxyl group, which is an oxygen atom single-bonded to a hydrogen atom, on the other side.
Amine
Aldehyde
Carboxylic acid
Ester
The functional group contains a carbonyl group, which is a carbon atom double-bonded to an oxygen atom, bonded to a carbon chain on one side of its carbon atom and a hydroxyl group, which is an oxygen atom single-bonded to a hydrogen atom, on the other side.
Amine
Aldehyde
Carboxylic acid
Ester
1 answer:
Answer:
Option-C (Carboxylic Acid)
Explanation:
Vinegar is a solution made up of 95 % water and 5 % Acetic Acid. The structure of Acetic Acid is shown below. Acetic acid belongs to a class of organic compounds called as Caboxylic Acids. The functional group of carboxylic acid contain a carbonyl group bonded to hydroxyl group and an alkyl group (highlighted red in structure).
Due to acid nature of this class it can donate the proton bonded to oxygen atom next to carbonyl group and resulting in the formation of resonance stabilized carboxylate ion.
Other examples of Carboxylic acids are,
HCOOH Formic Acid
CH₃-COOH Acetic Acid
CH₃-CH₂-COOH Propionic Acid
CH₃-CH₂-CH₂-COOH Butanoic Acid
CH₃-CH₂-CH₂-CH₂-COOH Pentanoic Acid
Option-C (Carboxylic Acid)
Explanation:
Vinegar is a solution made up of 95 % water and 5 % Acetic Acid. The structure of Acetic Acid is shown below. Acetic acid belongs to a class of organic compounds called as Caboxylic Acids. The functional group of carboxylic acid contain a carbonyl group bonded to hydroxyl group and an alkyl group (highlighted red in structure).
Due to acid nature of this class it can donate the proton bonded to oxygen atom next to carbonyl group and resulting in the formation of resonance stabilized carboxylate ion.
Other examples of Carboxylic acids are,
HCOOH Formic Acid
CH₃-COOH Acetic Acid
CH₃-CH₂-COOH Propionic Acid
CH₃-CH₂-CH₂-COOH Butanoic Acid
CH₃-CH₂-CH₂-CH₂-COOH Pentanoic Acid
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Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain molecules.
Avogadro's Number is =
which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.
Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.
Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.
Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.
We can calculate the number of molecules for each;
Number of molecules = ;
∴ Number of molecules = which will be =
Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.