Answer:
What is the range of the linear parent function
2 answers:
Answer:
The range of the linear parent function is all real numbers. It can also defined as (-∞,∞).
Step-by-step explanation:
The linear parent function is in the form of
This function is defined for all values of x. It means the domain of linear parent function is the set of all real numbers.
According to this function, the value of y is equal to the value of x. It means the function has same input and output values. It means the range of linear parent function is the set of all real numbers.
Therefore the range of the linear parent function is all real numbers. It can also defined as (-∞,∞).
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Answer:
a.y'=-1
b.y'=-1
c.Yes
Step-by-step explanation:
We are given that consider a function
Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable
Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.
a.
Differentiate w.r.t x then we get
b.
Differentiate w.r.t x then we get
When we substituting the value of y obtained from part b into a solution of part a then we get
Hence, solutions are consistent.
Refer to the figure shown below.
Because the question states that the semi circles are at the ends of the rectangle, each semicircle has a radius of 30 m.
The circumference of the oval is
2π(30) + 2*120 = 60π + 240 m = 428.5 m
The area of the oval is
π(30²) + 60*120 = 900π + 7200 m² = 1.0027 x 10⁴ m²
Note:
If the semi circles are placed on the 120-m sides of the rectangle, then similar calculations yield:
Circumference = 120π + 120 m = 497 m
Area = 3600π + 7200 m² = 1.851 x 10⁴ m²
Answer:
If the semi circles are placed on the 60-m sides of the rectangle, then
Circumference = 60π + 240 m, or 428.5 m
Area = 900π + 7200 m², or 1.0027 x 10⁴ m²
if the semi circles are placed on the 120-m sides of the rectangle, then
Circumference = 120π + 120 m, or 497 m
Area = 3600π + 7500 m², or 1.851 x 10⁴ m²
Because the question states that the semi circles are at the ends of the rectangle, each semicircle has a radius of 30 m.
The circumference of the oval is
2π(30) + 2*120 = 60π + 240 m = 428.5 m
The area of the oval is
π(30²) + 60*120 = 900π + 7200 m² = 1.0027 x 10⁴ m²
Note:
If the semi circles are placed on the 120-m sides of the rectangle, then similar calculations yield:
Circumference = 120π + 120 m = 497 m
Area = 3600π + 7200 m² = 1.851 x 10⁴ m²
Answer:
If the semi circles are placed on the 60-m sides of the rectangle, then
Circumference = 60π + 240 m, or 428.5 m
Area = 900π + 7200 m², or 1.0027 x 10⁴ m²
if the semi circles are placed on the 120-m sides of the rectangle, then
Circumference = 120π + 120 m, or 497 m
Area = 3600π + 7500 m², or 1.851 x 10⁴ m²