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ser-zykov [4K]
3 years ago
6

What is 900000+168763

Mathematics
2 answers:
IgorLugansk [536]3 years ago
6 0
The sum of the numbers is 1068763
Afina-wow [57]3 years ago
4 0
Your answer is 1,068,763
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What is the x intercept of 2x + 4y = 20
zhuklara [117]

Answer:

10

Step-by-step explanation:

x- intercept is where the equation intersect the x-axis. So, at x-axis y = 0

2x + 4*0 = 20

           2x = 20

Divide both sides by 2

2x /2 = 20/2

x = 10

4 0
3 years ago
Read 2 more answers
Along with this one please
Anarel [89]
X=5.2
Hope this was helpful
8 0
3 years ago
The formula to determine energy is E = 1/2mw? What is the formula solved for v?
Stella [2.4K]

Answer:

The formula to determine energy is E = 1/2mw? What is the formula solved for v?

Step-by-step explanation:

The formula to determine energy is E = 1/2mw? What is the formula solved for v?

5 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
Is (-5,-3) a solution of the following equations ? 6x-2y=24 , -10x-2y=-56
natulia [17]
6x-2y=24
6(-5)-2(-3)=24
-30+6=24
-24=24
Yes
-10x-2y=-56
-10(-5)-2(-3)=-56
50+6=-56
56=-56
Yes
The answer is= Yes. The solution is (-5.-3)
By the way, you have to show the work.
3 0
3 years ago
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