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Kruka [31]
2 years ago
15

BRO PLEASE ANYONE HELP ME

Mathematics
1 answer:
natita [175]2 years ago
8 0

Answer:

d 54.5x

Step-by-step explanation:

multiply x by the totals eventually will equal y

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Find the area under the standard normal curve between z = 1 and z = 2
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Answer:


Step-by-step explanation:

Find the area under the standard normal curve between z = 1 and z = 2.

  • <em>13.59% or 0.1359</em>
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3 0
3 years ago
Need help on this one​
11Alexandr11 [23.1K]

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slope is -1/7 and y intercept is 2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Help please and thank you
Oksi-84 [34.3K]

5/9(F-32°) plug in 185

5/9(185°-32°)

5/9(153)

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8 0
3 years ago
Midpoint between 8.5 and 8.6
iren [92.7K]
8.5+8.6=73.1÷2=36.55
formula for midpont a+b divide 2
                               
7 0
4 years ago
AREA ADDITION AND SUBTRACTION URGENT?
Novay_Z [31]

The area of shaded region is

A_{shaded}=A_{circle}-A_{segment}.

Find the area of circle and segment:

A_{circle}=\pi r^2=\pi (8.35)^2=69.7225\pi=219.0397,\\ A_{segment}=A_{sector}-A_{triangle},\\ \\A_{sector}=\dfrac{r^2 \alpha}{2} =\dfrac{(8.35)^2\cdot \frac{5}{9}\pi}{2}=19.3674\pi=60.8445,\\ \\A_{triangle}=\dfrac{1}{2}r^2\sin \alpha=\dfrac{1}{2}(8.35)^2\sin 100^{\circ}=34.3316,\\  \\A_{segment}=60.8445-34.3316=26.5129.

Then A_{shaded}=A_{circle}-A_{segment} =219.0397-26.5129=192.5268.

The area of shaded region rounded to the nearest tenth is 192.5 sq. ft.

Answer: 192.5 sq. ft.

6 0
3 years ago
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