Answer and Step-by-step explanation:
The concept of "shaping" is: "a term of behaviur that refers to slowly shaping or educating an organ to execute a particular response by improving any responses that come even close to the desired answer.
Let's take one rat example.
Here, in an experiment, a researcher may use moulding technique to coach a rat to push a lever.
To begin with, the researcher may award the rat if it does any movement in the lever direction at all. The rat will then simply take a step towards to the lever to be rewarded. Likewise, as the rat moves over to the lever and so forth, the rat also gets a reward before just pushing the lever generates reward.
Here the behaviour of the rat was 'formed' in order to make it push the lever. According to the example, any time the rat is awarded, it is praised for a "successive approximation" or for behaving in a manner that is nearer to the desired behaviour or result.
Likewise, algebraic equations are also progression steps and step-by - step progression allows solve the issue.
Answer:
-3.6 is a negative number compared to 1.2. 1.2 is -3 times less than -3.6. -3.6 is -3 times more than 1.2
Step-by-step explanation:
(can I get brainliest)
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
Answer:
=
Step-by-step explanation:
=
=
=
