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mario62 [17]
3 years ago
14

Two similar rectangles have a scale factor of 2:4. The perimeter of the large rectangle

Mathematics
1 answer:
fiasKO [112]3 years ago
5 0

Answer:

scale factor 2:4

80÷4×2=40

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Can anyone help me plz ?? Lakita has 66 water bottles for the 5K race participants. In addition, she is planning to buy boxes of
Ivanshal [37]

Answer:

65,81,97,113,129


Step-by-step explanation:


she has 65 water bottles and she is buying boxes of water bottles (x) that hold 16 water bottles each. She can only buy up to 5 water bottles.



f(x) = 16x + 65...where f(x) = total water bottles and x = number of boxes


x < = 5 here is ur restriction



the range is ur f(x) values which represent the total number of water bottles...keep in mind, she can only buy 5. Therefore, the numbers that can be subbing in for x are 0 thru 5.



So when subbing in 0 thru 5 for x, the results for f(x) are :


{ 65,81,97,113,129 }

8 0
3 years ago
What is the domain of the relation {(–2, 5), (0, 0), (3, –2), (4, 6)}
babunello [35]

Answer:

second option

Step-by-step explanation:

8 0
3 years ago
What is the equivalent mixed number to 50/7
never [62]
Well the first thing you have to do is find out how many times 7 goes into 50 whole. This is 7. So then you take the answer to (7x7) from 50 which gives you one, and put it over 50. This equals 7 + 1/50
7 0
3 years ago
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Fide the area of 7.7m×2.m
ivanzaharov [21]
15.4m Square because That is what I got when I times those two together 


6 0
3 years ago
Question 5
Darina [25.2K]

Answer:

the answer is 12.24 .

Step-by-step explanation:

that answer is right is because when you add of those you get 530 , then you divide by how many numbers there are which is 7 , which equals to 75.7 . when you get that number ( 75.7) you subtract that number to 65,90,85,70,70,95, and 55 . when you get the total of all of those you add those . which is 10.7, 14.3 , 9.3 , 5.7 , 5.7 , 19.3 , and 20.7 . from adding those you get 85.7. you divide by 7 and get 12.24 . hope this helps :) .

8 0
2 years ago
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