Two similar rectangles have a scale factor of 2:4. The perimeter of the large rectangle

How did the temperature change if: at first it decreased by 60% and then increased by 80%. PLEASE NEED HELP!

Sergio039 [100]

The temperature decreased by 28%

Step-by-step explanation:

How did the temperature change if :

At first it decreased by 60%
Then increased by 80%

Assume that the temperature before decreasing is 100%

∵ The temperature before decreasing = 100%

∵ It decreased by 60%

→ Before decreasing : decreasing : after decreasing

→ 100% : 60% : 100% - 60% = 40%

∴ The temperature after decreasing = 40%

Assume that the temperature after decreasing is 100%

∵ The temperature after decreasing = 100%

∵ It increased by 80%

By using the ratio method

→ After decreasing : increasing : after increasing

→ 100% : 80% : 100% + 80% = 180%

→ 40% : : x%

By using cross multiplication

∴ 100% × x% = 40% × 180%

- Divide both sides by 100%

∴ x% = $\frac{(40)(180)}{100}$

∴ x% = 72%

∵ At first the temperature = 100%

∵ At last the temperature = 72%

∵ The first the temperature > the last the temperature

∴ The decreasing in temperature = 100% - 72% = 28%

The temperature decreased by 28%

Learn more:

You can learn more about ratio in brainly.com/question/2707032

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5 0

2 years ago

The sum of the interior angle measures of a convex polygon is 540° . How many sides does it have?

Step2247 [10]

The answer
5
Explanation
The shape is a pentagon

7 0

2 years ago

What is the answer to X/9-1=4?

allsm [11]

X=32
Explanation: X/9-1=4
X/8=4
8x4=32

5 0

3 years ago

Read 2 more answers

You originally draw a design for an art contest on a 2 inch by 5 inch card. The second phrase of the contest requires the drawin

Bingel [31]

4.2.
If the 2 inch side was scaled to 10.5 inches the 5 inch side would be scaled by 10.5/2 = 5.25, so would be 25.125 inches which is too big.

So the 10.5 inches is the 5 inch side on the original, and so it 10.5/5 = 2.1 times bigger.

Therefore the smaller side would be 2*2.1/= 4.2 inches.

4 0

3 years ago

The volume of a rectangular box with a square base remains constant at 500 cm3 as the area of the base increases at a rate of 6

Andre45 [30]

Answer:

the rate at which the height of the box is decreasing is -0.0593 cm/s

Step-by-step explanation:

Given the data in the question;

Constant Volume of a rectangular box with a square base = 500 cm³

area of the base increases at a rate of 6 cm²/sec

so change in the area of the base with respect to time dA/dt = 6 cm²/sec

each side of the base is 15 cm long

so Area of the base = 15 cm × 15 cm = 225 cm²

the rate at which the height of the box is decreasing = ?

Now,

V = Ah

dv/dt = 0 ⇒ Adh/dt + hdA/DT = 0

⇒ dh/dt = -hdA/dt / A

we substitute

dh/dt = [ -( 500 / 225 ) × 6 ] / 225

dh/dt = [ -(2.22222 × 6) ] / 225

dh/dt = [ -13.3333 ] / 225

dh/dt = -0.0593 cm/s

Therefore, the rate at which the height of the box is decreasing is -0.0593 cm/s

7 0

2 years ago