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natita [175]
4 years ago
13

7th-grade math! Please help ASAP!

Mathematics
3 answers:
Jobisdone [24]4 years ago
8 0
The answer is the first answer
Vikentia [17]4 years ago
8 0

Answer:

Hey there!

First, we  can immidietly eliminate the negative answers, because it is impossible to have negative distance, or at least in 7th grade math :) Then, we see that -6/8-(-1/8)=-5/8. The absolute value is always positive, so the last choice is correct.

Let me know if this helps :)

catlover3783842 years ago
0 0

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Step-by-step explanation:

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Step-by-step explanation:

Consider the prided information.

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R_3\:\leftarrow \:R_3+\frac{1}{2}\cdot \:R_2\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&0&-\frac{3}{4}&2&-\frac{5}{4}\end{bmatrix}

R_2\:\leftarrow \:R_2-\frac{3}{2}\cdot \:R_3\ and\ R_1\:\leftarrow \:R_1-6\cdot \:R_3\\\begin{bmatrix}12&8&0&20&0\\ 0&-4&0&6&-2\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}\\R_2\:\leftarrow \:-\frac{1}{4}\cdot \:R_2\ , \ R_1\:\leftarrow \:R_1-8\cdot \:R_2\ and\ \:R_1\:\leftarrow \frac{1}{12}\cdot \:R_1\\\begin{bmatrix}1&0&0&\frac{8}{3}&-\frac{1}{3}\\ 0&1&0&-\frac{3}{2}&\frac{1}{2}\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}

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