$4[sin(x)]^2 - 2 = 0\implies 4[sin(x)]^2=2\implies [sin(x)]^2=\cfrac{2}{4}\implies [sin(x)]^2=\cfrac{1}{2} \\\\\\ sin(x)=\pm\sqrt{\cfrac{1}{2}}\implies sin^{-1}[sin(x)]=sin^{-1}\left( \pm\sqrt{\cfrac{1}{2}} \right)\implies x=sin^{-1}\left( \pm\sqrt{\cfrac{1}{2}} \right)$

$x=sin^{-1}\left( \pm\cfrac{\sqrt{1}}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{1}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{\sqrt{2}}{2} \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x=\cfrac{\pi }{4}~~,~~\cfrac{3\pi }{4}~~,~~\cfrac{5\pi }{4}~~,~~\cfrac{7\pi }{4}~\hfill$

Check the picture below.

4 0

2 years ago

Using the given points and line, determine the slope (0,32) and (100,212)

suter [353]

To solve for the slope given two lines, use the formula:

(y₂ - y₁)
----------
(x₂ - x₁)

Set one of the points as (x₁, y₁), and the other as (x₂, y₂).

(x₁, y₁) = (0,32)
(x₂, y₂) = (100,212)

plug into corresponding places:

(y₂ - y₁) (212 - 32) (180)
---------- = -------------- = -------
(x₂ - x₁) (100 - 0) (100)

180/100 is your slope

If you want simplified, it will be: 9/5

hope this helps

5 0

3 years ago

Determine the measure of each indicated angle. Show all necessary steps!

Rasek [7]

We know that a 4-sided polygon's angles add up to 360 degrees

so to find x:

360-(69+118+84)=89 degrees

For a 4-sided polygon we also know that the outside angles add up to 360 degree.

so to find p:

360-(100+62+106)=92 degrees

Hope it helps!

3 0

2 years ago