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antoniya [11.8K]
3 years ago
13

3 = −2∣ 1 — 4 s − 5 ∣ + 3

Mathematics
1 answer:
artcher [175]3 years ago
3 0

Answer:

s=1

Step-by-step explanation:

3=-2(1-4s-5)+3

3=-2+8s+10+3

3=8s+11

3-11=8s

8=8s

8/8=s

s=1

hope it helps you!!

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A plan that costs $29.99 another company $19.99 and $0.35 during nights and weekends for what numbers of night and weekend does
Masja [62]

Answer:

<em>29 minutes more</em>

Step-by-step explanation:

Let m represent minutes

changing the statement to algebra, since the second company charges a different rate at night and weekend  we have the equation below;

$19.99 + $0.35m > $29.99

Subtract 19.99 from both sides to isolate m and we have;

$19.99 -$19.99 + $0.35 > $29.99 - $19.99

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Divide both side by 0.35 to obtain the value of m;

\frac{0.35m}{0.35} > \frac{10}{0.35}

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5 0
3 years ago
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Using the graph below, identify 2 solutions to the inequality y&lt;-3/2x+2
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3 years ago
Find the simplified product b-5/2b x b^2+3b/b-5
White raven [17]

Answer:

The product \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Step-by-step explanation:

Given expression \frac{b-5}{2b} and \frac{b^2+3b}{b-5}

We have to find the product of  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

   

Consider the given expression  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

Multiply fractions, we have,

\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}

Cancel common factor ( b - 5 )

we have, =\frac{b^2+3b}{2b}

Apply exponent rule,

\:a^{b+c}=a^ba^c

b^2=bb

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=\frac{b\left(b+3\right)}{2b}

Cancel common factor b , we have,

=\frac{b+3}{2}

Thus, the product  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

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3 years ago
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