Answer:
12000 pounds is your answer
Answer:
235.2
Step-by-step explanation:
147 * 1.60 -> this way is an all in one calculation but to double check you can take 60% of 147 (147 * .60 = x ) and add that value to 147 so... 88.2+147=235.2
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
There are two solutions
AG =BG
mesDBG = mesEBG
