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Lubov Fominskaja [6]
3 years ago
9

Find the y-intercept for the line represented by the following equation. y=4/3-8

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

y = 4/3x - 8


y-intercept ⇒ when x = 0


y = 4/3 (0) - 8


y = -8


Answer: y -intercept = (0, -8)

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A pharmaceutical company sells bottles of 500 calcium tablets in two dosages: 250 milligram and 500 milligram. Last month, the c
Svetach [21]
X = 250 mg tabs
y = 500 mg tabs

2200x + 1800y = 39200....multiply by -1
2200x + 2200y = 44000
--------------------------------
-2200x - 1800y = - 39200 (result of multiplying by -1)
2200x + 2200y = 44000
--------------------------------add
400y = 4800
y = 4800/400
y = 12...... the 500 mg tabs (y) costs $ 12 per bottle

2200x + 2200y = 44000
2200x + 2200(12) = 44000
2200x + 26400 = 44000
2200x = 44000 - 26400
2200x = 17600
x = 17600/2200
x = 8 <== the 250 mg tabs (x) costs $ 8 per bottle
3 0
3 years ago
Read 2 more answers
7x - 3y + 12z This is algebra and I’m really bad at it
aalyn [17]
Wait, this is simplified because there are no common terms.
3 0
3 years ago
Given: PSTK is a trapezoid, m∠P=90° SK =13, PK = 12, ST=8 Find: The area of PSTK.
guajiro [1.7K]
<h3>Given</h3>

trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8

<h3>Find</h3>

the area of PSTK

<h3>Solution</h3>

It helps to draw a diagram.

∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as

... KS² = PS² + KP²

... 13² = PS² + 12²

... PS = √(169 -144) = 5

This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is

... A = (1/2)(b1 +b2)h

... A = (1/2)(12 +8)·5

... A = 50

The area of trapezoid PSTK is 50 square units.

5 0
3 years ago
Multiply or divide as indicated. x^4 • x^-2
Anettt [7]

The answer is 0 unless I did the math wrong


If so someone correct me. Other than that, hope this helped!

8 0
4 years ago
Read 2 more answers
HURRY PLEASE!<br> (g+2)^5
KengaRu [80]

Step-by-step explanation:

We need to use the binomial theorem/Pascal's triangle here.

(a+b)^5 = (5 choose 0)a^5 + (5 choose 1)a^4*b + (5 choose 2)a^3*b^2 + (5 choose 3)a^2*b^3 + (5 choose 4)a*b^4 + (5 choose 5)b^5.

5 choose 0 = 1

5 choose 1 = 5

5 choose 2 = 10

5 choose 3 = 10

5 choose 4 = 5

5 choose 5 = 1

And 1, 5, 10, 10, 5, 1, is the (5+1) = 6th row of pascal's triangle.

Therefore we get

g^5 + 5g^4*2 + 10g^3*2^2 + 10g^2*2^3 + 5g*2^4 + 2^5

which is

g^4 + 10g^4 + 40g^3 + 80g^2 + 80g + 32

Or, you could do the slow way, by just doing (g+2)(g+2)(g+2)(g+2)(g+2)

3 0
3 years ago
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