If the perimeter is 86in and the length is 25 what is the width

1 answer:

3 0

The answer is 18 because to find the perimeter you have to add length+width+width+length so we know that the length is 25 so we add 25+25 which is 50. then we subtract 86-50 which is 36. so we do 36 divided by 2 which gets us 18. Hope this Helps! :)

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6(3n+1)-3(-1+2n)=n+2

kap26 [50]

First, you want to distribute the 6 and the -3. This turns you equation into 18n+6+3-6n=n+2. Next, put all the n's on one side and numbers on the other. 18n-6n-n=2-6-3. Then, combine. 11n=-7 -> n=-7/11. Hope this helps!

7 0

3 years ago

An equilateral triangle has sides of length 2 units. A second equilateral triangle is formed having sides that are 150% of the l

murzikaleks [220]

Answer:

The percent increase in the perimeter is 337.5%

Step-by-step explanation:

The easiest way to approach this problem is by using consecutively the simple rule of three.

If the first triangle has sides of length two then, we can compute the second triangle's sides length as follows:

2 units------100%

X units------150%

this way

$X = 2*\frac{150}{100}\\ X =2*1.5\\X=3units$ .

Now for the third triangle we repeat the same process

3 units------100%

X units------150%

getting that the length of the sides for the third triangle is

$X = 3*\frac{150}{100}\\ X =3*1.5\\X=4.5units$ .

Now for the last triangle we repeat the same process

4.5 units------100%

X units------150%

getting that the length of the sides for the last triangle is

$X = 4.5*\frac{150}{100}\\ X =4.5*1.5\\X=6.75units$ .

Now, we need to know the perimeter of the first and last triangle. This can be calculated as the sum of the length of the sides of the triangle.

For the first triangle

$P_{first}=2+2+2\\P_{first}=6$

and for the last triangle

$P_{first}=6.75+6.75+6.75\\P_{first}=20.25$ .

To compute the percent increase in the perimeter from the first to the fourth triangle we will use one last simple rule of three (this time the percentage will be the variable)

6 units------100%

20.25 units------X%

$X = 100\frac{20.25}{6}\\ X=337.5\%$ .