I will assume here that we know the molar mass of sulfur, which is 32 g/mol (around).
this means that 0.5 moles will have half of it - the first option is correct!
8 moles will have 8 times this, which is 256 - the second option is not correct!
3 moles would have 96 grams -third option is not correct!
and we also know that 96 grams can't be 4 moles - so the forth option is not correct either
The math club bought 8 tacos and 16 burritos hope this helps
Answer:
113.75 miles
Step-by-step explanation:
well, the balloon original was of radius = 2 = r, he then put it 1 cm extra twice, so it went up to 4 = r. The balloon original had a radius of 2 and then it went up to 4.
![\bf \textit{volume of a sphere, \underline{originally}}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r = 2 \end{cases}\implies V=\cfrac{4\pi (2)^3}{3}\implies V=\cfrac{32\pi }{3} \\\\\\ \textit{volume of a sphere, \underline{later on}}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r = 4 \end{cases}\implies V=\cfrac{4\pi (4)^3}{3}\implies V=\cfrac{256\pi }{3} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20sphere%2C%20%5Cunderline%7Boriginally%7D%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%20%3D%202%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B4%5Cpi%20%282%29%5E3%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B32%5Cpi%20%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Bvolume%20of%20a%20sphere%2C%20%5Cunderline%7Blater%20on%7D%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%20%3D%204%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B4%5Cpi%20%284%29%5E3%7D%7B3%7D%5Cimplies%20V%3D%5Ccfrac%7B256%5Cpi%20%7D%7B3%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer: 155
Step-by-step explanation:
y=11x+12
2003-1990=13
13×11=143
y=143+12
155=143+12
