Given:
The function is:

To find:
The range of the given function.
Solution:
We have,

The range of secant inverse function is:

The range of the given function in interval notation is:
![Range=\left[0,\dfrac{\pi}{2}\right)\text{ and }\left( \dfrac{\pi}{2}, \pi\right ]](https://tex.z-dn.net/?f=Range%3D%5Cleft%5B0%2C%5Cdfrac%7B%5Cpi%7D%7B2%7D%5Cright%29%5Ctext%7B%20and%20%7D%5Cleft%28%20%5Cdfrac%7B%5Cpi%7D%7B2%7D%2C%20%5Cpi%5Cright%20%5D)
Therefore, the correct option is C.
Answer:
2,100
Step-by-step explanation:
$200 * 3.5= $700
$700 * 3= $2,100
1.6 : 4
1.6 is also equal to 8/5
therefore,
8/5 : 4
(8/5)/4
**get the reciprocal of the denominator (4) which is equal to 1/4**
(8/5)*(1/4)
(8/4)*(1/5)
2*(1/5)
2/5
two fifth is the answer
Look at the graph below carefully
Observe the results of shifting ={2}^{x}f(x)=2x
vertically:
The domain, (−∞,∞) remains unchanged.
When the function is shifted up 3 units to ={2}^{x}+3g(x)=2x +3:
The y-intercept shifts up 3 units to (0,4).
The asymptote shifts up 3 units to y=3y=3.
The range becomes (3,∞).
When the function is shifted down 3 units to ={2}^{x}-3h(x)=2 x −3:
The y-intercept shifts down 3 units to (0,−2).
The asymptote also shifts down 3 units to y=-3y=−3.
The range becomes (−3,∞).
I think you mean 'additives' and 'sum'
It's 8269 after you add it all together.