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3 years ago

What is the correct sequence of steps for calculating 946 on the scientific calculator?

Mathematics

1 answer:

n200080 [17]3 years ago

6 0

Answer:

9^6=531441

Step-by-step explanation:

To calculate ,on the Scientific calculator

-First press 9 marked on the set of numbers.

--Then go to the indices expression and press on it.

--After that press 6.

--You will get the value of 9^6=531441

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DiKsa [7]

Plz send a picture for me to help you on this thank u

5 0

3 years ago

A line intersects the points(-22,-14) and (-18,-12). What is the slope-intercept equation for this line?

zaharov [31]

Hello there,

Well we are going to start off with the equation to find the slope based on the given points:

$\frac{y_{2} - y_{1} }{x_{2} -x_{1} }$

Now using the two given points we are going to plug in and solve:

$\frac{(-12)-(-14)}{(-18)-(-22)}$ = $\frac{2}{4}$ = $\frac{1}{2}$

From this you know that $\frac{1}{2}$ is the slope of the equation. However, to find the y-intercept we are going to use y = mx+ b and plug in one of the points to solve:

(-14) = $\frac{1}{2}$ (-22) + b

(-14) = (-11) + b

-3 = b

That means that the y-intercept is at (0, -3). Lastly, we are just going to plug all this into the slope-intercept form:

y = $\frac{1}{2}$ - 3

Hope I helped,

Amna

6 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$