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Anna71 [15]
2 years ago
5

Solve the following equation for n: 4(n-1)=1.5n+5

Mathematics
2 answers:
DaniilM [7]2 years ago
5 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

\fbox \colorbox{black}{ \colorbox{white}{n} \:  \:  \:   \:  \:  \:  \: \: \colorbox{white}{=}  \:  \:  \:  \:  \:   + \colorbox{white}{3.6}}

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Let's solve for n ~

  • 4(n - 1) = 1.5n + 5

  • 4n - 4 = 1.5n + 5

  • 4n - 1.5n = 5 + 4

  • 2.5n = 9

  • n =  \dfrac{9}{2.5}

  • n =  \dfrac{90}{25}

  • n =  \dfrac{18}{5}

  • n \approx3.6

I hope it helps ~

4vir4ik [10]2 years ago
5 0
The answer is 3.6

work
4(n-1)=1.5n+5
4n-4=1.5n+5
4n=1.5n+9
2.5n=9
n=3.6
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lbvjy [14]

Answer:

3n−32=7n+28

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Step-by-step explanation:

Let's solve your equation step-by-step.

3n−32=7n+28

Step 1: Subtract 7n from both sides.

3n−32−7n=7n+28−7n

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Step 2: Add 32 to both sides.

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3 0
2 years ago
If someone could help it would be great :)
malfutka [58]

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2.2

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3 0
3 years ago
HURRY UP PLEASE !!
IRISSAK [1]

Answer:

<h2>The x-interecepts are 5.6 and -1.4, approximately.</h2>

Step-by-step explanation:

The given equation is

5x^{2} -21x=39

Where a=5, b=-21 and c=39, let's use the quadratic formula

x_{1,2}=\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a} =\frac{-(-21) (+-)\sqrt{(-21)^{2} -4(5)(-39)} }{2(5)}\\ x_{1,2}=\frac{21(+-)\sqrt{441+780} }{10}=\frac{21(+-35)}{10}\\x_{1}=\frac{21+35}{10}=\frac{56}{10} \approx 5.6\\  x_{2}=\frac{21-35}{10}=\frac{-14}{10} \approx -1.4

Therefore, the x-interecepts are 5.6 and -1.4, approximately.

7 0
3 years ago
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