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3 years ago

Solve the following equation for n: 4(n-1)=1.5n+5

Mathematics

2 answers:

DaniilM [7]3 years ago

5 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

$\fbox \colorbox{black}{ \colorbox{white}{n} \: \: \: \: \: \: \: \: \colorbox{white}{=} \: \: \: \: \: + \colorbox{white}{3.6}}$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's solve for n ~

$4(n - 1) = 1.5n + 5$

$4n - 4 = 1.5n + 5$

$4n - 1.5n = 5 + 4$

$2.5n = 9$

$n = \dfrac{9}{2.5}$

$n = \dfrac{90}{25}$

$n = \dfrac{18}{5}$

$n \approx3.6$

I hope it helps ~

4vir4ik [10]3 years ago

5 0

The answer is 3.6

work
4(n-1)=1.5n+5
4n-4=1.5n+5
4n=1.5n+9
2.5n=9
n=3.6

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3 years ago

Carlos buys a vintage automobile for $7300. He estimates that the value will increase by 3% every year. Estimate the value of th

lakkis [162]

Answer:

$9810.59

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Simple Interest Rate Formula: $\displaystyle A = P(1 + r)^t$

P is principle amount
r is rate
t is time (in years)

Step-by-step explanation:

Step 1: Define

Identify variables

P = 7300

r = 3% = 0.03

t = 10

Step 2: Solve for A

Substitute in variables [Simple Interest Rate Formula]: $\displaystyle A = 7300(1 + 0.03)^{10}$
(Parenthesis) Add: $\displaystyle A = 7300(1.03)^{10}$
Evaluate exponents: $\displaystyle A = 7300(1.34392)$
Multiply: $\displaystyle A = 9810.59$