Step-by-step explanation:
<u>A</u><u>B</u><u>C</u><u>D</u><u>E</u><u>F</u><u>G</u><u>H</u><u>I</u><u>J</u><u>K</u><u>L</u><u>M</u><u>O</u><u>P</u><u>Q</u><u>R</u><u>S</u><u>T</u><u>U</u><u>V</u><u>W</u><u>X</u><u>Y</u><u>Z</u>
Answer:
See Explanation
Step-by-step explanation:
<em>The question is incomplete as what is required of the question is not stated.</em>
<em>However, since the question is only limited to distance, a likely question could be to calculate the distance from Bayville to Colleyville.</em>
Represent the distance from Atlanta to Colleyville with AC
Represent the distance from Atlanta to Bayville with AB
Represent the distance from Bayville to Colleyville with BC
So, we have that:


The relationship between AB, AC and BC is:

Make BC the subject of formula:


Convert fraction to decimal


<em>Hence, the distance from Bayville to Colleyville is 14.8 miles</em>
Answer:
V = 5280 in^3
Step-by-step explanation:
The volume is found by
V = Bh where B is the area of the base and h is the height
first we need to find the area of the base
The base is the triangle
We need to find the base dimension for the triangle
34^2 = 16^2 + b^2
34^2 -16^2 = b^2
900 = b^2
30 =b
B = 1/2 bh
= 1/2 (30) *16
B =240
V = Bh
V = 240 * 22
V = 5280 in^3
9514 1404 393
Answer:
6. x = 3
8. x = -7.5
Step-by-step explanation:
Put the number in place of the expression it is equal to, then solve for x.
__
6) g(x) = -x +5
2 = -x +5 . . . . . . . . . g(x) is replaced by 2, because g(x) = 2
x +2 = 5 . . . . . . . . . . add x to both sides
x = 3 . . . . . . . . . . . . . subtract 2 from both sides
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8) n(x) = -2x -21
-6 = -2x -21 . . . . . n(x) is replaced by its equal: -6
3 = x +10.5 . . . . . . divide both sides by -2
-7.5 = x . . . . . . . . . subtract 10.5 from both sides
_____
<em>Additional comment</em>
We have shown a couple of ways these equations can be solved. You can separate the x-term and the constant terms before you divide by the x-coefficient, or you can do it after. In the first equation, we could have solved it ...
2 -x +5
-3 = -x . . . . subtract 5
3 = x . . . . . . multiply by -1
The way we did it avoids negative numbers.
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