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Answer:
D. One of the jellybeans that slipped out was orange and one was black
Step-by-step explanation:
We calculate the option with the highest probability of occurrence :
Total number of jellybean = 75
n(T) =75
n(Pink) = 8
n(red) = 22
n(Orange) = 17
n(green) = 8
n(white) = 6
n(black) = 4
We assume that the jelly beans must have slipped out one after the other.
Evaluating the options :
A.)
P(pink) and P(white)
8/75 * 6/74 = 0.0086486
B.)
P(green) and P(green)
8/75 * 7/74 = 0.0100900
C.)
P(white) and P(white)
6/75 * 5/74 = 0.0054054
D.)
P(orange) and P(black)
17/75 * 4/74 = 0.0122522
From the probability values obtained, the highest is D. Hence, the most likely to have occurred is One of the jellybeans that slipped out was orange and one was black
Answer:
1) x=8, y=138
2) x=110
Step-by-step explanation:
Target: ratio of pizza places / person < 0.01
<span>The
population of 15 blocks of the north side of town is 221 people per
block, but there are already 32 pizza places in the area.
population = 15*221 = 3,315
ratio: 32 pizza places / 3315 people = 0.0097 pizza places per person
Which indeed is less than 0.01 => this area is good for their purpose.
The population
of 22 blocks of the south area is 150 people per block, and there are
28 pizza places in the area.</span>
population: 22*150 = 3300
ratio: 28 pizza places / 3300 people = 0.00085 which is also less than 0.01
Both places meet the target of less than 0.01 places per person, but the south area seems better than north area.
Tan socks = 4
Grey socks = 7
Total number of socks = 4+7 = 11 socks
Probability of picking a tan sock then grey sock:
P(T)*P(G) = (4/11)*(7/10) = 14/54
Probability of picking a Grey sock then Tan sock
P(G)*P(T) = (7/11)*(4/10) = 14/55
Probability of two different colored socks
P(T&G)+P(G&T) = (14/55)+(14/55) = 28/55
Answer:
4 is c and 5 s a
Step-by-step explanation:
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