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rusak2 [61]
3 years ago
8

On a piece of paper, graph y=-3x-2

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0
Hope the answer helps!!!
:)

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Please help asap!!!!
Sergeu [11.5K]
(1,35)(2,60)(3,92)(4,120)(5,175)
7 0
3 years ago
In a random sample of students at a middle school 24 wanted to change the mascot and 30 wanted to keep the current mascot which
Yakvenalex [24]
30/54 =x/1,140
30*1140= 34200
34200/54 = 633.33
ANSWER:
Estimated- 633
7 0
3 years ago
The base of the 37 foot ladder is 9 feet from the wall of a building. will the top of the ladder reach a window ledge 35 feet ab
AnnZ [28]

Answer:

The answer to your question is Yes.

Step-by-step explanation:

The math in this problem is that we need to use the Pythagorean theorem to solve it. Pythagorean theorem is part of trigonometry a branch of Maths.

Data

base = 9 ft                      

length = 37 ft

height = ?

Pythagorean theorem

                                     c² = a² + b²

length = c

base = a

height = b

                                   37² = 9² + b²

-Solve for b

                                    b² = 37² - 9²

-Simplify

                                    b² = 1369 - 81

                                    b² = 1288

-Result

                                   b = 35.88

-Conclusion

The ladder will reach a height higher than 35 ft.  

8 0
3 years ago
Before 2017, a smart phone manufacturer's phones had a diagonal length of 5.8 inches and an aspect ratio
zhenek [66]

Answer: They were not correct it was bigger by 2.5 so the people were wrong

6 0
3 years ago
A Norman window is a window with a semi-circle on top of regular rectangular window. (See the picture.) What should be the dimen
Vikki [24]

Answer:

bottom side (a) = 3.36 ft

lateral side (b) = 4.68 ft

Step-by-step explanation:

We have to maximize the area of the window, subject to a constraint in the perimeter of the window.

If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}

The restriction is that the perimeter have to be 12 ft at most:

P=(a+2b)+\dfrac{\pi a}{2}=2b+a+(\dfrac{\pi}{2}) a=2b+(1+\dfrac{\pi}{2})a=12

We can express b in function of a as:

2b+(1+\dfrac{\pi}{2})a=12\\\\\\2b=12-(1+\dfrac{\pi}{2})a\\\\\\b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a

Then, the area become:

A=ab+\dfrac{\pi a^2}{8}=a(6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a)+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a^2+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}-\dfrac{\pi}{8}\right)a^2\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right)a^2

To maximize the area, we derive and equal to zero:

\dfrac{dA}{da}=6-2\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right )a=0\\\\\\6-(1-\pi/4)a=0\\\\a=\dfrac{6}{(1+\pi/4)}\approx6/1.78\approx 3.36

Then, b is:

b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a\\\\\\b=6-0.393*3.36=6-1.32\\\\b=4.68

3 0
3 years ago
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