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kupik [55]
3 years ago
9

Kesha needs to save $11 per hour. Write two estimates Kesha could use to determine how

Mathematics
1 answer:
kotegsom [21]3 years ago
7 0
She had $10 dollars and the 15 is far so you need to have only one estimate.
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Genelle is paid $1,122.38 semimonthly. What is her average monthly net or take home pay ?
sveta [45]

Answer: $2244.76

Step-by-step explanation:

Well, <em>semimonthly </em>means that she is paid the amount of $1,122.38 twice a month. I am making the assumption that taxes have already been taken out of this amount, and the amount listed above is how much she will take home. I then multiplied $1,122.38 × 2 which equaled $2244.76. This is how much Genelle will take home monthly.

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3 years ago
5-4x(x+2)=9<br> Find rhe X need the whole thing
nadya68 [22]

Answer:

x=-1 hope this helpsss

Step-by-step explanation:

3 0
3 years ago
I need help with 5 and 7
Thepotemich [5.8K]
I can't see them all the way
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3 years ago
What is the solution to 5 | x + 2 | - 6 = 9?<br>​
Yuki888 [10]

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1,-5

Step-by-step explanation:

8 0
3 years ago
University dean is interested in determining the proportion of students who receive some sort offinancial aid. rather than exami
vladimir2022 [97]
The confidence interval is
0.59\pm0.081

We first find p, our sample proportion.  118/200 = 0.59.

Next we find the z-score associated with this level of confidence:
Convert 98% to a decimal: 98% = 98/100 = 0.98
Subtract from 1:  1-0.98 = 0.02
Divide by 2:  0.02/2 = 0.01
Subtract from 1:  1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 2.33.

The margin of error (ME) is given by
ME=z\sqrt{\frac{p(1-p)}{n}}&#10;\\&#10;\\=2.33\sqrt{\frac{0.59(1-0.59)}{200}}=2.33\sqrt{\frac{0.2419}{200}}\approx0.081

This gives us the confidence interval 
0.59\pm0.081
8 0
4 years ago
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