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ale4655 [162]
3 years ago
5

If a function f(x)=x^3 has the domain {-3,0,2,4} what is it's range

Mathematics
2 answers:
agasfer [191]3 years ago
7 0

Step-by-step explanation:

Range is y-values

= {-27,0,8,64}

torisob [31]3 years ago
4 0
27, 0, 8, 64
All u need to do is cube all the numbers in the domain
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I dont understand this
Reil [10]
U basically solve: (4sqrt8)*2 + (5 sqrt 12 + 6 sqrt 20)*2
5 0
3 years ago
Read 2 more answers
You have 6 pints of glaze. It takes 7/8 of a pint to glaze a bowl and 9/16 of a pint to glaze a plate.
son4ous [18]

Answer:

a. How many bowls could you glaze?

6 bowls

How many plates could you glaze?

10 plates

b. You want to glaze 5 bowls, and then use the rest for plates.

How many plates can you glaze?

2 plates

How much glaze will be left over?

8/9 of glaze would be left

c. How many of each object could you glaze so that there is no glaze left over? Explain how you found your answer.

4 4/23 bowls and 4 4/23 plates

Step-by-step explanation:

We are told in the question

Number of pints of glaze = 6 pints

Number of pints to glaze a bowl= 7/8 of pint

Number of pints to glaze a plate = 9/16 of a pint

a.

How many bowls could you glaze?

7/8 pint = 1 bowl

6 pints = x

Cross Multiply

x = 6 pints/ 7/8

= 6 × 8/7

= 48/7

= 6.8571428571 bowls

We can only glaze whole numbers of a bowl, hence, we can only glaze 6 bowls

How many plates could you glaze?

9/16 pint = 1 bowl

6 pints = y

y = 6 pints/ 9/16

= 6 × 16/9

= 10.666666667 plates

We can only glaze whole number of a plate, hence, we can only glaze 10 plates

b. You want to glaze 5 bowls, and then use the rest for plates.

1 bowl = 7/8 pints

5 bowls = z

Cross Multiply

z = 5 × 7/8pints

= 4 3/8 pints of glaze would be used for bowls

How many plates can you glaze?

The rest is for plates, hence:

The amount of glaze left for plates is calculated as:

6 pints - 4 3/8

1 5/8 pints of glaze would be left over to glaze plates.

So therefore,

9/16 pints = 1 plate

1 5/8 pints =

= 2 8/9

Hence we can only glaze 2 plates

How much glaze will be left over?

2 8/9 pints - 2 pints

= 8/9 pints of glaze.

c. How many of each object could you glaze so that there is no glaze left over?

We have 6 pints of glaze

Number of pints to glaze a bowl= 7/8 of pint

Number of pints to glaze a plate = 9/16 of a pint

Let the number of each objects be represented by x

7/8 × x + 9/16 × x = 6 pints

= 4 4/23 bowls and 4 4/23 plates

3 0
3 years ago
Find the surface area
shusha [124]

Answer:

59.4

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
X^2+y^2=169, 3x+2y=39 please answer using substitution and each step
Oksanka [162]

Answer:

x=13,y=0

Step-by-step explanation:

We are given a system of equations

{x}^{2}  +  {y}^{2}  = 169 -  - eqn \: 1 \\ 3x + 2y = 39 -  - eqn \: 2

For equation 1,square all terms to reduce it

√x²+√y²=169

x+y=13

Make x the subject as required by the question to use substitution method

x=13-y

Plug x=13-y into eqn 2

3(13-y)+2y=39

39-3y+2y=39

39-y=39

y=39-39=0

Plug y=0 into equation 1

x+0=13

x=0

7 0
2 years ago
Can someone check my answer & explain?
Novay_Z [31]

Answer:

The answer should be 3 cubic cm

Step-by-step explanation:

First you have to get the area of the right triangle base 1/2 bh. That would be 2x3/2=3

To find volume, you plug the area in the volume formula

v=1/3 ah

v=1/3 (3)(3)

1/3(9) would be 3 cubic cm

4 0
3 years ago
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