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3 years ago

If a function f(x)=x^3 has the domain {-3,0,2,4} what is it's range

Mathematics

2 answers:

agasfer [191]3 years ago

7 0

Step-by-step explanation:

Range is y-values

= {-27,0,8,64}

torisob [31]3 years ago

4 0

27, 0, 8, 64
All u need to do is cube all the numbers in the domain

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Read 2 more answers

A cone has a radius of 5 ft and a height of 15 ft. It is empty and is being filled with water at a constant rate of 15 15 ft 3 f

kvasek [131]

Answer:

$\frac{dr}{dt}=0.11062ft/sec$

Step-by-step explanation:

From the question we are told that:

Radius $r=5ft$

Height $H=15ft$

Rate $R=15ft/3sec =5ft/s$

Surface Radius $R_{surf}=2.2ft$

Generally the equation for Volume is mathematically given by

$V=\frac{1}{3}\pi*r^2h$

Since radius to height ratio gives

$\frac{r}{h}=\frac{5}{15}$

$\frac{r}{h}=\frac{1}{3}$

$h=3r$

Therefore

$V=\frac{1}{3}\pi*r^2(3r)$

$V=\pi r^3$

Generally the equation for Change of Volume is mathematically given by

$\frac{dv}{dt}=\pi \frac{d}{dt}(r^3)$

$\frac{dv}{dt}=\pi 3*r^2 \frac{dr}{dt}$

$\frac{dv}{dt}=\pi 3*(2.2)^2 \frac{dr}{dt}$

$\frac{dr}{dt}=\frac{5}{45.62}$

$\frac{dr}{dt}=0.11062ft/sec$

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3 years ago