P-6=19; p=13
so you just plug the value of P into the problems P and solve the equation
(13) - 6 = 19
7=19
so...that's incorrect because 7 can't equal 19 making the problem No solution. if that's wrong then idk what they're teaching in math any more...
Answer:
Step-by-step explanation:
1) we have to solve the associated equation
-16x^2 + 24x + 16 = 0
-2x^2 + 3x + 2 = 0
2x^2 -3x -2 = 0
Δ = 9 + 16 = 25
x1 = (3 + 5)/4= 2
x2 = (3 - 5)/4 =-1/2
the x intercepts are -1/2 and 2
2) a maximum because the parabola opens downwards (the first term is negative)
V(x) = -b/2a = -24/-32 = 3/4
V(y) = -16(9/16) + 24(3/4) + 16 = -9+18 + 16 = 25
V(3/4,25)
3) for draw a parabola is are necessary the coordinates of the vertex and of two points: one that lies to left of the vertex, and one that lies on the right to the vertex.
So we already have the necessary informations to draw it.
It is 20.000 plus 2.000 plus 50 plus 6
Ten to the power of five.
(x-3)^2 / (271/2) + y^2 / (271/4)=1.
Hope I helped☺☺
