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3 years ago

1 pts Given that XY =4 and YZ =14, find the measure of angle x to the nearest degree.

Mathematics

1 answer:

k0ka [10]3 years ago

4 0

Step-by-step explanation:

its a triangle so find XZ then use cosine rule to find angle X

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100 POINTS!!!!! I REALLY NEED HELP!!!!

vekshin1

Answer:

The answer would be 221

Step-by-step explanation:

there is a 20 customer difference from 22 to 42 and 42 customers gave 91 in tips. 22 customers gave 73 in tips. you need to find the answer for 100 people so what you do is you take the 174 that the 80 customers gave in tips and add 47 to 174 and you get the answer

5 0

3 years ago

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The two right triangular prisms are similar solids.

Zanzabum

Answer:

<h2>The volume of the larger prims is eight times greater than the smaller prism.</h2>

Step-by-step explanation:

If the scale factor of the larger prims to the smaller prism is 3, that means each side is triple.

We know the a triangular prims has a volume defined by

$V_{small} =\frac{b \times h_{1} }{2} \times h_{2}$

If we take that formula as the smaller prism, then the larer prism has a volum of

$V_{large} =\frac{2b \times 2h_{1} }{2} \times 2h_{2}=8(\frac{b \times h_{1} \times h_{2} }{2} )$

If we compare, we can deduct that

$V_{large}=8V_{small}$

In words, the volume of the larger prims is eight times greater than the smaller prism.

4 0

3 years ago

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An avid traveler is investigating whether travel websites differ in their pricing. She chooses a random sample of 32 hotel rooms

Tatiana [17]

The answer is D beachside trust

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2 years ago

Consider the following information related to a set of quantitative sample data:

svlad2 [7]

Answer:

(a) There are outliers

(b) $x$ and $x >62$

Step-by-step explanation:

Given

$\sigma = 14.92$

$\bar x = 22.0$

$q_0 = -24$

$q_1 = 14.5$

$q_2 = 24.5$

$q_3 = 33.5$

$q_4 = 64$

Solving (a): Check for outliers

This is calculated using:

$Lower = Q_1 - (1.5 * IQR)$ --- lower bound of outlier

$Upper = Q_3 +(1.5 * IQR)$ --- upper bound of outlier

Where

$IQR = Q_3 - Q_1$

So, we have:

$IQR = 33.5 - 14.5$

$IQR = 19$

The lower bound of outlier becomes

$Lower = Q_1 - (1.5 * IQR)$

$Lower = 14.5 - (1.5 * 19)$

$Lower = 14.5 - 28.5$

$Lower = -14$

The upper bound of outlier becomes

$Upper = Q_3 +(1.5 * IQR)$

$Upper = 33.5 + 1.5 * 19$

$Upper = 33.5 + 28.5$

$Upper = 62$

So, we have:

$-14 \le x \le 62$ --- the range without outlier

Given that:

$q_0 = -24$ --- This represents the lowest data

$q_4 = 64$ --- This represents the highest data

-24 and 64 are out of range of $-14 \le x \le 62$ .

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

$x$ and $x >62$

4 0

3 years ago

at maximum speed , an airplane travels 1680 miles against the wind in 5 hours flying with the wind , the plane can travel the sa

Westkost [7]

X = velocity of plane
y = velocity of wind

x - y = 1680/5 = 336 mph .....(1) [ plane flying against the wind]
&
x + y = 1680/4 = 420 mph....(2) [ plane flying with the wind]

Adding (1) and (2) to eliminate y gives

2x = 756
x = 378 mph is the speed of the plane with no wind.

3 0

3 years ago

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