Answer:
Step 1: Expected value = -2.53 dollars
He makes - 1,803.89 dollars over 713 of these bets.
Step 2:
Step-by-step explanation:
Expected value of bet = (Winning probability * winning amount) - (losing probability * losing amount)
Winning probability = (13/52) * (12/51) = 0.0588
Losing probability = 1 - 0.0588 = 0.9412
Expected value = (37 * 0.0588) - (5 * 0.9412)
Expected value = -2.53 dollars
If this same bet of expected value -2.53 dollars is made 713 times, our expected losses are:
2.53 * 713 = 1,803.89 dollars
Thus he makes - 1,803.89 dollars over 713 of these bets.
Answer:
YES
Step-by-step explanation:
It does
if you think about the difference between the first term of y and the first term of x it is 4. then you take the difference between the second term of y and the second term of x which is 7. Then take the difference between the third value of y and the third value for x which is 10. The difference between those differences is 3 which is constant!
Hope that helps :)
Answer:
126
Step-by-step explanation:
multuply the base times the hight in which case the base is 21 and the hight is 12 then devide that answer by 2. so it should look like this 21 * 12 all over 2
<span>So before we can participate in our Chem labs, we need to answer questions regarding the experiment. I'm not the best at Chemistry and I'm having some trouble with this one problem.
Here's the experiment's instructions (Part A)
And the problem, "When performing today’s experiment, your lab partner decides to add all the reagents into one beaker instead of two separate beakers. After adding everything together and waiting a significant amount of time, you see no reaction occur. What was the problem?"
Could it be that all of the separate beakers form different mixtures and just adding everything together at once doesn't allow that to happen? I have honestly have no clue, any help is appreciated</span>
